declaring constant array without initializing all the elements

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  • Pavan

    declaring constant array without initializing all the elements

    Hi,
    I need to create a consant array of larze size but however its
    elements can be calculated using an equation, say for example I need
    an int arry of 20 elements where each element will be

    arr[i] = 2 + (i*i)

    But I want arry to be constant. How can I declare such a constant
    array without actually defining all the elements?

    I could think of one way:
    Declare a non const arry

    int arr_non_const[20];
    for(int i=0; i <20; i++)
    {
    arr_non_const[i] = 2 + (i*i);
    }

    Now declare a constant pointer

    const int* arr = arr_non_const;

    Is it correct? Is there any other way to do so.
  • Abhishek Padmanabh

    #2
    Re: declaring constant array without initializing all the elements

    On Mar 3, 7:10 pm, Pavan <pavan...@gmail .comwrote:
    Hi,
        I need to create a consant array of larze size but however its
    elements can be calculated using an equation, say for example I need
    an int arry of 20 elements where each element will be
    >
    arr[i] = 2 + (i*i)
    >
    But I want arry to be constant. How can I declare such a constant
    array without actually defining all the elements?
    >
    I could think of one way:
    Declare a non const arry
    >
    int arr_non_const[20];
    for(int i=0; i <20; i++)
    {
       arr_non_const[i] = 2 + (i*i);
    >
    }
    >
    Now declare a constant pointer
    >
    const int* arr = arr_non_const;
    >
    Is it correct? Is there any other way to do so.
    Yes, you can do it that way and expose just 'arr' to the external code
    that is supposed to use that array.

    You can make the arr_non_const as a global pointer initialized by a
    initializer function call which holds the actual array (either static
    storage duration or dynamically allocated to increase lifetime) but in
    an unnamed namespace and fill it up with whatever logic you have
    (initializer function). Then declare the pointer 'arr' as you have
    above as a global one as well but you declare it as extern (as in C++
    const variables have internal linkage), so as to be accessible in
    other places.

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    • James Kanze

      #3
      Re: declaring constant array without initializing all the elements

      On Mar 3, 4:30 pm, Lionel B <m...@privacy.n etwrote:

      [...]
      Now one thing you can do is
      const int const_arr = [20] = { 2, 3, 6, 11, 18, ... } // you have to
      explicitly initialize the array with the 20 elements
      As I understood it, the OP explicitly required that the array
      elements "... be calculated using an equation", so I suspect
      that this would not work for them.
      If the equation is known at compile time, it's pretty easy to
      write a program which will generate the definition of the array,
      with all of its initializers. I do this a lot (although I do
      remember having problems with it in one case: the array
      contained a couple of million members, and the compiler wouldn't
      handle it.)
      One technique which might be made to work if the
      initialisation function were simple/suitable, would be some
      template meta-programming trick, where you get the compiler to
      perform the calculation, the canonical example being a
      compile-time calculated factorial:
      This would be total overkill, though, I suspect.
      It's a nice trick for obfuscation, but generating the code with
      a separate program is a lot easier and more readable.

      --
      James Kanze (GABI Software) email:james.kan ze@gmail.com
      Conseils en informatique orientée objet/
      Beratung in objektorientier ter Datenverarbeitu ng
      9 place Sémard, 78210 St.-Cyr-l'École, France, +33 (0)1 30 23 00 34

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