typedf inC++

[nanimun]

i facing one problem that is

i was used "typedf"to main function as followes

typedf int main(void)
{
int a=10;
cout<<"name";
cout<<"adress";
cout<<a
} nanimun

this is i was done
i dotknow what is the pronlem
plz help me

[mohammadazim]

You are tring to do typedef of a function definetion. That is not possible.
You can do typedef of a function declaration as
typedef int main(void);
but then it won't allow you to define main in the same file and if you write a c program without a main, it will give linking error "undefined reference to main".

But I don't understand why you want to do this. Actually we do tydef so that we can use the typename instead of declaring same type of thing again. If your requirement is same, why don't you use some other name like
tydef int func(void);

May be I did't understood your requirement. Don't consider my response your answer. I'll also wait for some one else to answer you.

[nanimun]

just tellme that
how it is declared

[mohammadazim]

typedef int main(void);