Calling operator() via a Pointer

[Paul Bilokon]

Hi all,

A very simple question, but I couldn't find a definitive answer in the literature. Functors provide you with the function call syntax:

foo(1, 2, 3)

may be a call to a functor. Now, what if I have a pointer to a functor instead? Is the following syntax the recommended, or perhaps the only, way to call operator() on a functor pointer:

fooPtr->operator()(1, 2, 3)

Many thanks!

Regards,
Paul

[weaknessforcats]

I assume you are nit using the STL since STL functions cannot have more than 2 arguments.

That said, your code is correct. You can also:
[code=cpp]
(*fooptr)(1,2,3 );
[/code]

[Paul Bilokon]

Thanks a lot, weaknessforcats .

No, I am not using STL; it's my own custom functor.

I prefer your syntax, as it emphasises the function call semantics, rather than the "operator() ".

Many thanks,
Paul