Is it true I do like below, if I want to all data array? and the ouput is 2. How to know which array that computer take?
[code=cpp]
#include <iostream>
#include <conio.h>
#include <cstdlib>
#include <math.h>
#include <stdio.h>
#include <time.h>
using namespace std;
int i, j;
int x[6];
int A[6], B[6], C[6], D[6], E[6], F[6];
// The members of the array int minimum = numbers[0] ;
int minimum;
int main(void)
{
{
for(i=1;i<7;i++ )
{
for(i=1;i<7;i++ )
{
x[i]=i;
A[i]=(2+pow(x[i],2));
B[i]=(1+pow(x[i],3));
C[i]=(2+pow(x[i],2)-1);
D[i]=(3*pow(x[i],3));
E[i]=(1+pow(x[i],2));
F[i]=(3+pow(x[i],2));
}
{
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] A[%d]=%d\n", i,1, i, A[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] B[%d]=%d\n", i,2, i, B[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] C[%d]=%d\n", i,3, i, C[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] D[%d]=%d\n", i,4, i, D[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] E[%d]=%d\n", i,5, i, E[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] F[%d]=%d\n", i,6, i, F[i]);
}
}
}
}
printf("\n");
printf ("A\tB\tC\tD\tE \tF");
printf ("\n_\t_\t_\t_\ t_\t_\t");
for(i=1;i<7;i++ )
{
cout<<endl;
printf("%d\t", A[i]);
printf("%d\t", B[i]);
printf("%d\t", C[i]);
printf("%d\t", D[i]);
printf("%d\t", E[i]);
printf("%d\t", F[i]);
}
// Compare the members
minimum = A[i], B[i],C[i], D[i], E[i], F[i]; for (int i = 1; i < 7; ++i)
{
if (A[i], B[i],C[i], D[i], E[i],F[i] < minimum)
minimum = A[i], B[i],C[i], D[i], E[i],F[i]; }
printf("\n");
// Announce the result
cout << "The lowest member value of the array is "<< minimum << "." << endl;
return 0;
}[/code]
[code=cpp]
#include <iostream>
#include <conio.h>
#include <cstdlib>
#include <math.h>
#include <stdio.h>
#include <time.h>
using namespace std;
int i, j;
int x[6];
int A[6], B[6], C[6], D[6], E[6], F[6];
// The members of the array int minimum = numbers[0] ;
int minimum;
int main(void)
{
{
for(i=1;i<7;i++ )
{
for(i=1;i<7;i++ )
{
x[i]=i;
A[i]=(2+pow(x[i],2));
B[i]=(1+pow(x[i],3));
C[i]=(2+pow(x[i],2)-1);
D[i]=(3*pow(x[i],3));
E[i]=(1+pow(x[i],2));
F[i]=(3+pow(x[i],2));
}
{
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] A[%d]=%d\n", i,1, i, A[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] B[%d]=%d\n", i,2, i, B[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] C[%d]=%d\n", i,3, i, C[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] D[%d]=%d\n", i,4, i, D[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] E[%d]=%d\n", i,5, i, E[i]);
}
printf("\n");
for(i=1;i<7; i++)
{
printf("[%d][%d] F[%d]=%d\n", i,6, i, F[i]);
}
}
}
}
printf("\n");
printf ("A\tB\tC\tD\tE \tF");
printf ("\n_\t_\t_\t_\ t_\t_\t");
for(i=1;i<7;i++ )
{
cout<<endl;
printf("%d\t", A[i]);
printf("%d\t", B[i]);
printf("%d\t", C[i]);
printf("%d\t", D[i]);
printf("%d\t", E[i]);
printf("%d\t", F[i]);
}
// Compare the members
minimum = A[i], B[i],C[i], D[i], E[i], F[i]; for (int i = 1; i < 7; ++i)
{
if (A[i], B[i],C[i], D[i], E[i],F[i] < minimum)
minimum = A[i], B[i],C[i], D[i], E[i],F[i]; }
printf("\n");
// Announce the result
cout << "The lowest member value of the array is "<< minimum << "." << endl;
return 0;
}[/code]
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