typecasting problem

[Ray D.]

Okay, so I'm trying to typecast a random integer into a double, and
store that in an array of doubles. Here is my code:


void randomMatrix(do uble *x) {

int i, random;

// Generate pseudo-random sequence
// Restrict range to 9
for(i = 0; i < SIZE; i++){
random = rand()%9;
printf("random is %i, ", random);

x[i] = (double)random;
printf("%i\n", x[i]);
}
}

I call this function twice, and here is the output for each time (Note
that SIZE = 6 in the loop above)

random is 8, 1075838976
random is 7, 1075576832
random is 6, 1075314688
random is 1, 1072693248
random is 1, 1072693248
random is 2, 1073741824

random is 6, 1075314688
random is 3, 1074266112
random is 3, 1074266112
random is 0, 0
random is 4, 1074790400
random is 5, 1075052544


As you can see, I first print out the integer returned from the rand()
function, then I attempt to typecast to a double and print this, but
it's pretty clear they do not match, any idea what is going on?? I
appreciate any help you may have! Thanks.

[Walter Roberson]

Re: typecasting problem

In article <1193421934.207 754.326800@19g2 000hsx.googlegr oups.com>,
Ray D. <ray.delvecchio @gmail.comwrote :

>Here is my code:

>void randomMatrix(do uble *x) {

int i, random;

x[i] = (double)random;
printf("%i\n", x[i]);

You are passing a double to printf, but telling printf that you
are passing an integer. If you want to see the stored double value,
try %f as the format.
--
"Any sufficiently advanced bug is indistinguishab le from a feature."
-- Rich Kulawiec

[Ray D.]

Re: typecasting problem

Touchee, can't believe I didn't notice that!

On Oct 26, 2:19 pm, rober...@ibd.nr c-cnrc.gc.ca (Walter Roberson)
wrote:

In article <1193421934.207 754.326...@19g2 000hsx.googlegr oups.com>,
>
Ray D. <ray.delvecc... @gmail.comwrote :

Here is my code:
void randomMatrix(do uble *x) {
int i, random;
x[i] = (double)random;
printf("%i\n", x[i]);

>
You are passing a double to printf, but telling printf that you
are passing an integer. If you want to see the stored double value,
try %f as the format.
--
"Any sufficiently advanced bug is indistinguishab le from a feature."
-- Rich Kulawiec

[Default User]

Re: typecasting problem - TPA

Ray D. wrote:

Touchee, can't believe I didn't notice that!

Please don't top-post. Your replies belong following or interspersed
with properly trimmed quotes. See the majority of other posts in the
newsgroup, or:
<http://www.caliburn.nl/topposting.html >

[Martin Ambuhl]

Re: typecasting problem

Ray D. wrote:

Okay, so I'm trying to typecast a random integer into a double, and
store that in an array of doubles. Here is my code:

Note that the cast is completely worthless.

>
void randomMatrix(do uble *x) {
>
int i, random;
>
// Generate pseudo-random sequence
// Restrict range to 9
for(i = 0; i < SIZE; i++){
random = rand()%9;
printf("random is %i, ", random);
>
x[i] = (double)random;
printf("%i\n", x[i]);

^^
This is an error

}
}

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define SIZE 6

void randomMatrix(do uble *x)
{

int i, random;

for (i = 0; i < SIZE; i++) {
random = 9. * rand() / (1. + RAND_MAX); /* restrict range to
0..8 */
printf("random is %i, ", random);

x[i] = random; /* useless cast removed */
printf("%g\n", x[i]); /* fixed printf specifier; Was "%i",
which is for ints, but x[i] is a
double. */
}
}

int main(void)
{
double theArray[SIZE];
srand(time(0)); /* you may want to fix this to handle
cases where the value of a time_t
may be outside the range of an
unsigned int */
randomMatrix(th eArray);
putchar('\n');
randomMatrix(th eArray);

return 0;
}

random is 8, 8
random is 7, 7
random is 0, 0
random is 4, 4
random is 5, 5
random is 7, 7

random is 5, 5
random is 5, 5
random is 3, 3
random is 3, 3
random is 2, 2
random is 3, 3

[CBFalconer]

Re: typecasting problem

"Ray D." wrote:

>
Okay, so I'm trying to typecast a random integer into a double,
and store that in an array of doubles. Here is my code:
>
void randomMatrix(do uble *x) {
>
int i, random;
>
// Generate pseudo-random sequence
// Restrict range to 9
for(i = 0; i < SIZE; i++){
random = rand()%9;
printf("random is %i, ", random);
>
x[i] = (double)random;
printf("%i\n", x[i]);
}
}

Try printing a double format, rather than an integer format. Also
make sure that the passed in matrix (*x) is big enough to hold all
the values. That means malloc it with:

x = malloc(SIZE * sizeof *x);

--
Chuck F (cbfalconer at maineline dot net)
Available for consulting/temporary embedded and systems.
<http://cbfalconer.home .att.net>



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