how for loop works ...

[ponnuvel9]

for(i=0;0;i++)
{
printf("Its me");
}

This code prints the string "Its me" only once.
How it works?
Because, the condition should fail, even for the first time rite?

[cornfed]

The middle value, 0 in ur example, should have a equation (Like i=0) In the first i=0 u just specify the fact that i starts counting at 0.

for(i=0;0;i++)
{
printf("Its me");
}

This code prints the string "Its me" only once.
How it works?
Because, the condition should fail, even for the first time rite?

[amitpatel66]

for(i=0;0;i++)
{
printf("Its me");
}

This code prints the string "Its me" only once.
How it works?
Because, the condition should fail, even for the first time rite?

Yes because you have said 0 in the for loop.
try below to print the message 9 times:

[code=c]
for(int i=0;i<10;i++)
{
printf("Its me");
}
[/code]

Can you see the change in my code and your code??

[amitpatel66]

for(i=0;0;i++)
{
printf("Its me");
}

This code prints the string "Its me" only once.
How it works?
Because, the condition should fail, even for the first time rite?

The for loop prints the value once becuase the second value 0 is checked after the value of i is incremented first time.
when i becomes 1, it checks for condition which returns 0 (ie false) and exits the loop

[weaknessforcats]

This code:

int i;
for(i=0;0;i++)
{
printf("Its me");
}

prints nothing. (Using Visual Studio.NET 2005).

The int i is set to 0 and then tested. 0 is false. Loop terminated.

Who says its displays once?? Did you use a do loop?? Is this a test ??