How to print 64 bit integer using sprintf() family

[jannlin]

I have a need to print 64 bit integer in Windows and UNIX environments.

Code Snipet:

unsigned __int64 mNumRowsRead=12 34567890123456;

sprintf(buf, "%d row(s) read", mNumRowsRead);
sprintf(buf, "%s row(s) read", mNumRowsRead);
sprintf_s(buf, "%d row(s) read", mNumRowsRead);
itoa(mNumRowsRe ad,buff2,10);
cout << buff2 << endl;
sprintf_s(buf, "%s row(s) read", buff2);

First sprintf converted the 64 bit integer to 32 bits. The out interger is 1015724736 instead of 123456789012345 6.
Second sprintf throws exception.
Third sprintf_s behavior like first one.
Last sprintf_s throws exception without itoa(). With itoa() the number was truncated. itoa() must not be able to handle 64 bit integer as expected. So, do we have 64 bit version of itoa()?? Or how do I print a 64 bit integer as part of a string. Thanks for the help.

[Banfa]

On windows you need to let sprintf know it is a 64 bit integer using the I64 prefix
[code=c]
sprintf(buf, "%I64d row(s) read", mNumRowsRead);
[/code]

more information here

[jannlin]

On windows you need to let sprintf know it is a 64 bit integer using the I64 prefix
[code=c]
sprintf(buf, "%I64d row(s) read", mNumRowsRead);
[/code]

more information here

Thanks for the help. I suppose I need to use I64u for unsigned 64 bit integer. Is I64d for signed 64 bit integer? Thanks.

[Banfa]

Thanks for the help. I suppose I need to use I64u for unsigned 64 bit integer. Is I64d for signed 64 bit integer? Thanks.

That's correct, it's all in the link I provided.