One and two - dimensional array passing

[VanKha]

If I have an array int a[10] (just for example) , I can pass the array to a function void myf ( int * x) with the call myf ( a ) . But with the 2-dimensional array int a[10][10] , using myf ( int ** x ) ( or ( int a[][]) with the call myf ( a ) will generate an error (unrelated pointed types , etc..) . Why ?

[VanKha]

Please help me . Thanks a lot.

[JosAH]

Please help me . Thanks a lot.

Note that a two dimensional array is just a one dimensional array where each of
its elements happen to be one dimensional arrays as well.

Similar to passing a one dimensional array 'a', where the parameter 'a' is considered
a pointer to its first element, as in:

[code=c]
char array[42]; // first element is a char
f(a);
...
void f(char* a) { ... }
[/code]

so is the two dimensional array considered a pointer to its first element:

[code=c]
char array[42][54]; // first element is a char[54]
f(a);
...
void f(char *a[54]) { ... }
[/code]

kind regards,

Jos

[weaknessforcats]

Not correct:

char array[42][54]; // first element is a char[54]
f(a);
...
void f(char *a[54]) { ... }

This shows the argument to be an array of 54 character pointers. What is needed is a pointer to an array of 54 characters:

[code=cpp
char array[42][54]; // first element is a char[54]
f(a);
...
void f(char (*a)[54]) { ... }
[/code]