Parsing the content of string array into an integer

[Alien]

Hi guys,

I am trying to create to parse the content of a char array into integer as follows but I cant do it and keep getting the following error. Any solution or suggestion is welcome.

*************** *************** *************
#include <stdio.h>
#include <ctype.h>

int main()
{
char isbn[20];
int weight[10] = {10,9,8,7,6,5,4 ,3,2,1};

int numericisbn[20];

int product;
int sum = 0;


printf("Enter your ISBN number: ");
fgets(isbn, 20, stdin);

int i;
for (i = 0; i < strlen(isbn); i++)
{

numericisbn[i] = atoi(isbn[i]);

}
printf("%d\n", numericisbn[0]);
printf("%d\n", numericisbn[1]);
printf("%d\n", numericisbn[3]);
}


*************** *************** *************
The code compiles and the error message I get is:

Segmentation fault(core dumped)



Any help or suggestion is appreciated.

[JosAH]

error: parse error at end of input

Any help or suggestion is appreciated.

That is a compilation error; most likely you're missing a right curly brace near
the end of your code. Check them carefully and you'll find the missing one.

The atoi() function takes a '\0' terminated string and returns the int represented
by that string; it shouldn't be a problem if your array contains just digits.

kind regards,

Jos

[Alien]

That is a compilation error; most likely you're missing a right curly brace near
the end of your code. Check them carefully and you'll find the missing one.

The atoi() function takes a '\0' terminated string and returns the int represented
by that string; it shouldn't be a problem if your array contains just digits.

kind regards,

Jos

Yes, it my code was missing closing curly braces of main() function.

The problem I had was parseing error which after fixing the code is:

string.c: In function `main':
string.c:22: error: parse error before '{' token
string.c: At top level:
string.c:26: error: parse error before '}' token

My array is meant to take numbers and dashes "-" which is why I am checking (or rather trying to) each element of the array and sort it into another array of type int (called numericisbn).

The article is about ISBN of books. As you know it comes with dashes alongside numbers, I am basically trying to filterout the dashes.

Regards.

Alien.

[JosAH]

Yes, it my code was missing closing curly braces of main() function.

The problem I had was parseing error which after fixing the code is:

string.c: In function `main':
string.c:22: error: parse error before '{' token
string.c: At top level:
string.c:26: error: parse error before '}' token

Told you so ;-) We'd have to see the whole code if you want those parse errors
solved. Seeing the error diagnostic messages it has to do with curly brackets
that aren't balanced; same as the previous errors.

kind regards,

Jos

[Alien]

Told you so ;-) We'd have to see the whole code if you want those parse errors
solved. Seeing the error diagnostic messages it has to do with curly brackets
that aren't balanced; same as the previous errors.

kind regards,

Jos

Thanks. :) The code is just above.

Thanks for going through the trouble.

[JosAH]

Thanks. :) The code is just above.

Thanks for going through the trouble.

Huh? you edited your original post: see your text and the part I thought I quoted.
Now you're talking about a runtime error: you're invoking the atoi() function on a
single char; that is not correct; atoi() takes a pointer to char(s) as its parameter,
terminated by a '\0' char.

kind regards,

Jos

[Alien]

Huh? you edited your original post: see your text and the part I thought I quoted.
Now you're talking about a runtime error: you're invoking the atoi() function on a
single char; that is not correct; atoi() takes a pointer to char(s) as its parameter,
terminated by a '\0' char.

kind regards,

Jos

Since atoi() wont work, is there any other functions that you recommend? I am fairly new to the language and there isn't many that i know of that's likely to do the jobs for me.

Thanks and regards.

[Alien]

Ok, I got down to here:

*************** *************** *************** ********
for (i = 0; i < strlen(isbn); i++)
{
if(isdigit(isbn[i]))
{
numericisbn[i] = isbn[i];
puts("isdigit is working\n");
}
}
printf("These are the contents of numericisbn: ");
printf("%d\n", numericisbn[0]);
printf("%d\n", numericisbn[1]);
printf("%d\n", numericisbn[2]);
printf("%d\n", numericisbn[3]);
printf("%d\n", numericisbn[4]);
printf("%d\n", numericisbn[5]);


The output is:

Enter your ISBN number: 12s2
isdigit is working

isdigit is working

isdigit is working

These are the contents of numericisbn: 49
50
0
50
0
0
0
0
0


*************** *************** *************** ********

All is good as expected. When I put the "s" amonst the number, the isdigit() function sorted it out and put a 0 in place.

Now those values I get for 1 2 and 2 are ASCII equivalent. Can someone tell me how to convert those ASCII to proper ints?

The issue obviously lies in the line bolded above. Since atoi() wont work I have exhausted all my knowledge on this. Any ideas anyone?

Regards.


BTW, the reason why you see all the 0s as the output of printf() is because i ran a for loop before the code above which clears the numericisbn[10] of all its memory addresses and puts 0 inplace.

[mohammadazim]

In your loop you can do following changes

for (i = 0; i < strlen(isbn); i++)
{
if(isdigit(isbn[i]))
{
char s[2];
s[1] = '\0';
s[0] = isbn[i];
numericisbn[i] = atoi(s);
printf("%d", numericisbn[i]);
puts("isdigit is working\n");
}
}

Since we have only one api(atoi) which converts integer strings to inytegers, it is better to make it a temp string and get an int.

[Alien]

In your loop you can do following changes

for (i = 0; i < strlen(isbn); i++)
{
if(isdigit(isbn[i]))
{
char s[2];
s[1] = '\0';
s[0] = isbn[i];
numericisbn[i] = atoi(s);
printf("%d", numericisbn[i]);
puts("isdigit is working\n");
}
}

Since we have only one api(atoi) which converts integer strings to inytegers, it is better to make it a temp string and get an int.

Thanks a lot mate. I'll try the solution above when i get a chance.

Regards.

[Alien]

Yep it work.

Once again thank you very much.