Differentiation between pre and post increment operator

[mohammad ismail aakhil]

i have overladed unary ++ both pre and postfix increment operator using member function. both the operator function differ by arguements.v use a additional argunent of type int.
how does complier differentiate between pre and post increment operator.

[JosAH]

i have overladed unary ++ both pre and postfix increment operator using member function. both the operator function differ by arguements.v use a additional argunent of type int.
how does complier differentiate between pre and post increment operator.

When the compiler see this: "++foo" it generates code for the (overloaded)
pre-increment operator and when the compiler see this: "foo++" it generates
code for the (overloaded) post-increment operator. T* operator++() is the prefix
increment operator and T* operator++(int) is the postfix increment operator
for your type T.

kind regards,

Jos

[weaknessforcats]

Adding to what JosAH has already said, the int argument is a hack by the C++ language architects. Without it, the prefix and postfix member functions would have the same function prototype. So an int was arbitrarily added to make them unique.

If you try to use the int argument, your compiler will produce an error that says operator++ does not take any arguments.