10 numbers per line

[manjina3]

Hi guys! How do i display 10 numbers per line when i run this code?

[code=c]
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv) {
long NumberOfLines = 10;
long count = 10;
long incr = 1;


if (argc > 1) {
count = strtol(argv[1], 0, 10);
}

if (count < 1){
printf("Invalid count! Using 10 instead.\n");
count = 10;

}

if (argc > 2) {
incr = strtol(argv[2], 0, 10);
}

if (incr < 1){
printf("Invalid increment! Using 1 instead.\n");
incr = 1;

}

if (argc > 3) {
NumberOfLines = strtol(argv[3], 0, 10);
}

if (NumberOfLines > 10){
printf("%s, \n"0);
NumberOfLines = 10;
}
printf("T minus ");
while (count > 0) {
printf("%d, ", count);
count -= incr;
}

if(count == 0){

printf("BLASTOF F!\n");
return 0;
}

else{
printf("and holding...\n");
return 0;
}


}[/code]

[debasisdas]

As you have posted a question in cafe it is being moved to c/c++ forum

MODERATOR.

[gpraghuram]

Hi guys! How do i display 10 numbers per line when i run this code?


#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv) {
long NumberOfLines = 10;
long count = 10;
long incr = 1;


if (argc > 1) {
count = strtol(argv[1], 0, 10);
}

if (count < 1){
printf("Invalid count! Using 10 instead.\n");
count = 10;

}

if (argc > 2) {
incr = strtol(argv[2], 0, 10);
}

if (incr < 1){
printf("Invalid increment! Using 1 instead.\n");
incr = 1;

}

if (argc > 3) {
NumberOfLines = strtol(argv[3], 0, 10);
}

if (NumberOfLines > 10){
printf("%s, \n"0);
NumberOfLines = 10;
}
printf("T minus ");
while (count > 0) {
printf("%d, ", count);
count -= incr;
}

if(count == 0){

printf("BLASTOF F!\n");
return 0;
}

else{
printf("and holding...\n");
return 0;
}


}

HI,
Can u add code tags to your code and post it.
Also what output r u getting when running this.?

Raghuram

[manjina3]

HI,
Can u add code tags to your code and post it.
Also what output r u getting when running this.?

Raghuram

This is the code that i'm having trouble with. When the code is run the first argument specifies the starting count and the second the decrement. It also needs to display no more than 10 numbers per line

ps this code now works when compiled

[code=c]
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv) {
long count = 10;
long incr = 1;


if (argc > 1) {
count = strtol(argv[1], 0, 10);
}

if (count < 1){
printf("Invalid count! Using 10 instead.\n");
count = 10;

}



if (argc > 2) {
incr = strtol(argv[2], 0, 10);
}

if (incr < 1){
printf("Invalid increment! Using 1 instead.\n");
incr = 1;

}


printf("T minus ");
while (count > 0) {
printf("%d, ", count);
count -= incr;
}

if(count == 0){

printf("BLASTOF F!\n");
return 0;
}

else{
printf("and holding...\n");
return 0;
}


}
[/code]

[Girish Kanakagiri]

This is the code that i'm having trouble with. When the code is run the first argument specifies the starting count and the second the decrement. It also needs to display no more than 10 numbers per line

ps this code now works when compiled

[code=c]
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv) {
long count = 10;
long incr = 1;


if (argc > 1) {
count = strtol(argv[1], 0, 10);
}

if (count < 1){
printf("Invalid count! Using 10 instead.\n");
count = 10;

}



if (argc > 2) {
incr = strtol(argv[2], 0, 10);
}

if (incr < 1){
printf("Invalid increment! Using 1 instead.\n");
incr = 1;

}


printf("T minus ");
while (count > 0) {
printf("%d, ", count);
count -= incr;
}

if(count == 0){

printf("BLASTOF F!\n");
return 0;
}

else{
printf("and holding...\n");
return 0;
}


}
[/code]

put a conditional statement to check the numbers displayed by incrementing
printCount each time when you print a number; if printCount mod 10 equals
zero then print a new line character.

Regards,
Girish.