Spacing the output of Pascal's Triangle

[harishram007]

Sorry for the inconvienience but i am expecting this pattern the pattern is in the attachment....i am just pasted my code and want alterations.... please help
but i am ending up wid something like

1
1 1
1 2 1
1 3 3 1
with the following code
[code=cpp]
#include <iostream.h>
void main()
{
int n,y,x,c;
cin >> n;
for (y = 0; y < n; y++)
{
c = 1;
for (x = 0; x <= y; x++)
{
cout<<" "<<c<< " ";
c = c * (y - x) / (x + 1);
}
cout<<endl;
}
cout<<endl;
}
[/code]
so please can someone help me out in spacing!

[JosAH]

Sorry for the inconvienience but i am expecting this pattern
1
1 1
1 2 1
1 3 3 1
but i am ending up wid something like

1
1 1
1 2 1
1 3 3 1
with the following code

which looks good to me (they're identical, so what's the problem?)

kind regards,

Jos

[sicarie]

Please read these thoroughly.

Thanks

Update:: You have already been asked to read the Posting Guidelines throughly, so if you violate them again, I'm afraid I will have to issue you a temporary ban. If you want to post on the site, you have to follow the rules.

[sicarie]

Check out the setw() command.

[harishram007]

but where do i place the setw()

[sicarie]

but where do i place the setw()

I'd start by putting it in front of your first 1. You're going to have to play around with it and figure it out for yourself. This might require a variable to keep track of what level of the triangle you are at, and probably figuring out a spacing in between each of the numbers on a line...

[weaknessforcats]

I'd start by putting it in front of your first 1. You're going to have to play around with it and figure it out for yourself. This might require a variable to keep track of what level of the triangle you are at, and probably figuring out a spacing in between each of the numbers on a line...

What sicarie says will work. I suggest you write your display down on paper so you can count the spaces you need for each line of Pascal's Triangle.

[bitgeek]

try this code:

#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
  double n;
  cout << "Number: ";
  cin >> n;
  cin.ignore();
  for (int y = 0; y < n; y++)
  {
    int c = 1;
    cout << setw(n-y);

    for (int x = 0; x <= y; x++)
    {
      cout  << c << " ";
      c = c * (y - x) / (x + 1);

    }
    cout << "\n";
  }
  cin.get();
  }

[Banfa]

Actually the problem is not quite as simple as it seems, the amount of spcing required is not only dependent on the current output line but the total number of lines that will be output.

For example it is fairly easy to see that the large the number of lines output the further over the 1 on the first line will have to be to leave room for the data on the following lines.