access computed variable name

[ccodehelp]

Hi,

I have a variable's name stored in a character string:

char* a = "access_me" ;

How can I access this variable? Let's say access_me is also of type char* and I want to have functionality of:

printf("%s", access_me);

Thanks.

[Meetee]

Hi,

I have a variable's name stored in a character string:

char* a = "access_me" ;

How can I access this variable? Let's say access_me is also of type char* and I want to have functionality of:

printf("%s", access_me);

Thanks.

You can write it as
printf("%s", a); and it will print access_me.

Regards

PS Hope I have understood your problem correcty!

[ccodehelp]

You can write it as
printf("%s", a); and it will print access_me.

Regards

PS Hope I have understood your problem correcty!

I over-simplified my porblem perhaps and of course this is correct. But what I intended actually was:

I have 'access' stored in char* a. I want to access a variable name constructed from it. like I am appending _func to all these variables, I actually want to access access_func.

[weaknessforcats]

have 'access' stored in char* a. I want to access a variable name constructed from it. like I am appending _func to all these variables, I actually want to access access_func.

There is no access to the variable name at run time. Everything has been converted to binary. You can't even tell what language the program wwas written in.