Template traits

[Aarti]

I was trying my hand on a template class and i am getting a
compilation error

error C2146: syntax error : missing ';' before identifier
'isOptimizedImp lAvailable'. Any pointers would be of great help.
Here is my code

#include <iostream>

using namespace std;

template<typena me T>
class foo_traits
{
public:
static bool customImpl;
};

template<>
class foo_traits<int>
{
public:
static bool customImpl;
};

template<>
class foo_traits<char >
{
public:
static bool customImpl;
};

bool foo_traits<char >::customImpl = false;
bool foo_traits<int> ::customImpl = true;

template<typena me T>
class foo
{
public:
typename foo_traits<T>:: customImpl isOptimizedImpl Available()
{
return foo_traits<T>:: customImpl;
}
};



int main()
{
foo<intf;
}

[Kai-Uwe Bux]

Re: Template traits

Aarti wrote:

I was trying my hand on a template class and i am getting a
compilation error
>
error C2146: syntax error : missing ';' before identifier
'isOptimizedImp lAvailable'. Any pointers would be of great help.
Here is my code
>
#include <iostream>
>
using namespace std;
>
template<typena me T>
class foo_traits
{
public:
static bool customImpl;
};
>
template<>
class foo_traits<int>
{
public:
static bool customImpl;
};
>
template<>
class foo_traits<char >
{
public:
static bool customImpl;
};
>
bool foo_traits<char >::customImpl = false;
bool foo_traits<int> ::customImpl = true;
>
template<typena me T>
class foo
{
public:
typename foo_traits<T>:: customImpl isOptimizedImpl Available()

bool isOptimizedImpl Available()

{
return foo_traits<T>:: customImpl;
}
};
>
>
>
int main()
{
foo<intf;
}

Best

Kai-Uwe Bux

[Aarti]

Re: Template traits

On Jul 12, 9:02 pm, Kai-Uwe Bux <jkherci...@gmx .netwrote:

Aarti wrote:

I was trying my hand on a template class and i am getting a
compilation error

>

error C2146: syntax error : missing ';' before identifier
'isOptimizedImp lAvailable'. Any pointers would be of great help.
Here is my code

>

#include <iostream>

>

using namespace std;

>

template<typena me T>
class foo_traits
{
public:
static bool customImpl;
};

>

template<>
class foo_traits<int>
{
public:
static bool customImpl;
};

>

template<>
class foo_traits<char >
{
public:
static bool customImpl;
};

>

bool foo_traits<char >::customImpl = false;
bool foo_traits<int> ::customImpl = true;

>

template<typena me T>
class foo
{
public:
typename foo_traits<T>:: customImpl isOptimizedImpl Available()

>
bool isOptimizedImpl Available()
>

{
return foo_traits<T>:: customImpl;
}
};

>

int main()
{
foo<intf;
}

>
Best
>
Kai-Uwe Bux- Hide quoted text -
>
- Show quoted text -

WOW that worked. But just for curiosity.. why did returning
foo_traits<T>:: customImpl fail?

[Kai-Uwe Bux]

Re: Template traits

Aarti wrote:

On Jul 12, 9:02 pm, Kai-Uwe Bux <jkherci...@gmx .netwrote:

>Aarti wrote:

I was trying my hand on a template class and i am getting a
compilation error

>>

error C2146: syntax error : missing ';' before identifier
'isOptimizedImp lAvailable'. Any pointers would be of great help.
Here is my code

>>

#include <iostream>

>>

using namespace std;

>>

template<typena me T>
class foo_traits
{
public:
static bool customImpl;
};

>>

template<>
class foo_traits<int>
{
public:
static bool customImpl;
};

>>

template<>
class foo_traits<char >
{
public:
static bool customImpl;
};

>>

bool foo_traits<char >::customImpl = false;
bool foo_traits<int> ::customImpl = true;

>>

template<typena me T>
class foo
{
public:
typename foo_traits<T>:: customImpl isOptimizedImpl Available()

>>
>bool isOptimizedImpl Available()
>>

{
return foo_traits<T>:: customImpl;
}
};

>>

int main()
{
foo<intf;
}

>>
>Best
>>
>Kai-Uwe Bux- Hide quoted text -
>>
>- Show quoted text -

>
WOW that worked. But just for curiosity.. why did returning
foo_traits<T>:: customImpl fail?

Because foo_traits<T>:: customImpl is not a type but a boolean static
variable. Putting the keyword "typename" before that identifier will not
magically change its meaning.


Best

Kai-Uwe Bux
Best