didnt terminate

[19831030]

I have send my code,It print some no without ending.but i cant found the fault point can u help me

#include <stdio.h>
#include <string.h>
	
int main(int argc, char *argv[])
  {
	int i;
	int j;
	int k;
	int m;
	int ptr;	
k=0;
printf("0");
putchar('\n');
	for(i=2;i<argc;i++)
   {
	for (j=1;j<i;j++)
	{	
	ptr = strcmp(argv [j], argv[i]);
	if(ptr==0)
	{

argv[i]=argv[i+1];
i--;
printf("%d",(j-1));
//putchar('\n');
goto loop;
	}
}
{
k++;
printf("%d",k);
loop:
putchar('\n');
}
}
return 0;
}

[weaknessforcats]

for(i=2;i<argc; i++)
{
etc...

argc?

That's the number of arguments on the command line. There must be at least 3 arguments or this loop will run forever.

I do not understand your logic here. What are you trying to do?

[19831030]

argc?

That's the number of arguments on the command line. There must be at least 3 arguments or this loop will run forever.

I do not understand your logic here. What are you trying to do?

Hi!
I enter arguments at the run time (./a.out {aa,bb,aa,cc,de ,dg,cc,cc,jhe}) like this.I use this code for numbered those string and if there are 2 or more string in same I wanna put a same index for that.So required o/p for above set is (0,1,0,2,3,4,2, 2,5) like this.Your help is highly appreciate & pls help me to solve this,bcos still I couldnt solve this.
Thanks

[Darryl]

Look at line 14, then look at line 23 above.

i++ and i-- = loop forever!!!

[JosAH]

Also see this thread.

kind regards,

Jos