Compiler padded structure as output.

[arunraj2002in]

Is their any way to find compiler padded structure as output.
Ex:
struct{ int a; char b; int c;} ..
now after padding the structure will be
struct{ int a; char b;pad1; pad2; int c;}.. i actually want this as an output. Is it possible & how?

[Silent1Mezzo]

Is their any way to find compiler padded structure as output.
Ex:
struct{ int a; char b; int c;} ..
now after padding the structure will be
struct{ int a; char b;pad1; pad2; int c;}.. i actually want this as an output. Is it possible & how?

I'm pretty sure this isn't possible. You could find how much the compiler added in padding by doing sizeof(struct name);

You would just take that number and subtract the sizeof every individual item inside the struct.

[weaknessforcats]

Create an object of your struct and take the address of each member.

If you have a char, the address of the next member subtracted from the address of the char member will give the pad on the char.

[code=c]
struct Test
{
int a;
char b;
int c;
};
int main()
{
Test obj;
int b = reinterpret_cas t<int>(&obj.b) ;
int c = reinterpret_cas t<int>(&obj.c) ;
cout << c - b << endl;
}
[/code]

Visual Studio.NET shows c -b as 4. That is, the char occupies 4 bytes. Hence, there are 3 pad bytes after the char.