length of integer or numeric values

[sheriff]

Hi frds,

As i am getting an input value of integer (for ex: 1.413) and i want to limit the number of characters in the input value to 5

for ex:

1.413
14.13
141.3

double y;
cout<<"Enter the new value of displacement: ";
cin>>y;

the ouput

Enter the new value of displacement:_ _ _ _ _


it shud not accept the input more than 5 characters

if it is a string i can limit by using length () or size() function

i cant convert them as a string and use it further

wat can i do?

[svlsr2000]

Hi frds,

As i am getting an input value of integer (for ex: 1.413) and i want to limit the number of characters in the input value to 5

for ex:

1.413
14.13
141.3

double y;
cout<<"Enter the new value of displacement: ";
cin>>y;

use cin.getline() to take the input in a array then use strtof function to convert to float.


the ouput

Enter the new value of displacement:_ _ _ _ _


it shud not accept the input more than 5 characters

if it is a string i can limit by using length () or size() function

i cant convert them as a string and use it further

wat can i do?

use cin.getline() to get the input, using this you can limit the input.
then use strtof to convert to float
have a look at this

http://www.unet.univie.ac.at/aix/libs/basetrf1/atof.htm

[sheriff]

thx svlsr

ok i will get them as a string first

but i cant limit the character

string string1;
cin.getline(string1,5);

it saying

no matching function for cin.getline

i hav also tried this

string string1;
int z=5;
cin.getline(string1,z);

i cant able to use any delimiter too as i am giving input

[Savage]

thx svlsr

ok i will get them as a string first

but i cant limit the character

string string1;
cin.getline(string1,5);

it saying

no matching function for cin.getline

i hav also tried this

string string1;
int z=5;
cin.getline(string1,z);

i cant able to use any delimiter too as i am giving input

But why using unformmated input when u can use formated input.

e.g

[CODE=cpp]string c;

cin.width(6) //must also count '\0' character

cin>>c;[/CODE]

Savage

[sheriff]

But why using unformmated input when u can use formated input.

e.g

[CODE=cpp]string c;

cin.width(6) //must also count '\0' character

cin>>c;[/CODE]

Savage

thx savage

but while giving input(with width fuction) it accepts more than 6 characters

i want to limit the characters

that i shud not able to give input more than 6 characters

[Savage]

thx savage

but while giving input(with width fuction) it accepts more than 6 characters

i want to limit the characters

that i shud not able to give input more than 6 characters

U can input more then six characters but only six of them are stored.

And there is also a peek member of the cin that returns next input,so u can test it

Savage

[sheriff]

ya u r right !! savage

it is taking only 6 characters

thx a lot

till my next question bye!!

Happy weekend

[svlsr2000]

thx svlsr

ok i will get them as a string first

but i cant limit the character

string string1;
cin.getline(string1,5);

it saying

no matching function for cin.getline

i hav also tried this

string string1;
int z=5;
cin.getline(string1,z);

i cant able to use any delimiter too as i am giving input

getline doesnot take string as arguement
try some like this
char temp[6]
cin.getline(tem p,6);
getline expects char * as first arguement.
If u want to use string you can use
string s;
cin.getline(s.c _str(),s.size() );

[Savage]

ya u r right !! savage

it is taking only 6 characters

thx a lot

till my next question bye!!

Happy weekend

I'm more than happy to help u.

Savage

[weaknessforcats]

This is not correct:

[/quote=svlsr2000]
getline expects char * as first arguement.
If u want to use string you can use
string s;
cin.getline(s.c _str(),s.size() );
[/quote]

This will not compile. cin.getline() expects a char* argument. the c_str() method of string returns a representation of the string as a non-modifiable C-string, that is, a const char*.

You have to remember that a string does not contain a C-string.