simple problem with delete []

[michael]

Hi All,

I have the following:

const int LENGTH = 5;

void limitNameLength (string inText, char *&outText, int outLength){
if(static_cast< int>(inText.len gth()) outLength){
inText = inText.substr(0 , outLength);
}
strcpy(outText, inText.c_str()) ;
if(static_cast< int>(strlen(out Text)) < outLength){
for(int i = strlen(outText) ; i < outLength; i++){
outText[i] = ' ';
}
}
outText[outLength] = static_cast<cha r>(NULL);
}

int main(){
char *temp;
string name = "some long name";

temp = new char[LENGTH];
cout << "before : " << name << "\n";
limitNameLength (name, temp, LENGTH);
cout << "after : " << temp << "\n";

delete [] temp;
return 0;
}

if I comment out the call to limitNameLength the delete [] works ok. If I
don't the delete [] never returns.....
Can anyone tell me why? As far as I can see all I have done is pass the
array to another function to manipulate it a bit then delete it. Why does
delete not work?

Thanks for your help

Michael

[kakaxyl2002@yahoo.com.cn]

Re: simple problem with delete []

Hello:

When I programed this one in MinGW stdio.It worked very well.

And I didn't find any grammer error in yours.

[Ivan Vecerina]

Re: simple problem with delete []

"michael" <spam@begone.ne twrote in message
news:46455386$0 $9097$5a62ac22@ per-qv1-newsreader-01.iinet.net.au ...
: Hi All,
:
: I have the following:
:
: const int LENGTH = 5;
:
: void limitNameLength (string inText, char *&outText, int outLength){
You can have char* outText - no need to make it a reference
since the function does not change the pointer address itself.
: if(static_cast< int>(inText.len gth()) outLength){
: inText = inText.substr(0 , outLength);
: }
: strcpy(outText, inText.c_str()) ;
: if(static_cast< int>(strlen(out Text)) < outLength){
: for(int i = strlen(outText) ; i < outLength; i++){
: outText[i] = ' ';
: }
: }
All of the previous can be simply written as:
void limitNameLength ( string const& inText
, char *outText, int const outLength)
{
strncpy( outText, inText.c_str(), outLength );
//NB: if outLength<inTex t.size(), there will be no final '\0'

: outText[outLength] = static_cast<cha r>(NULL);
why not just: '\0' ?

This effectively relies on outText having a length
of outLength+1 !

: }
:
: int main(){
: char *temp;
: string name = "some long name";
:
: temp = new char[LENGTH];
: cout << "before : " << name << "\n";
: limitNameLength (name, temp, LENGTH);
: cout << "after : " << temp << "\n";
:
: delete [] temp;
: return 0;
: }
:
: if I comment out the call to limitNameLength the delete [] works ok.
If I
: don't the delete [] never returns.....
: Can anyone tell me why? As far as I can see all I have done is pass
the
: array to another function to manipulate it a bit then delete it. Why
does
: delete not work?

When you allocate an array of size LENGTH, the valid indices
are 0 .. LENGTH-1. limitNameLength writes over outText[LENGTH].

The buffer provided to limitNameLength needs to have 1 more character
than the requested maximum length of the string.
If outLength is to be the maximum buffer size, you could change
the last line to:
outText[outLength-1] = '\0';



--
http://ivan.vecerina.com/contact/?subject=NG_POST <- email contact form
Brainbench MVP for C++ <http://www.brainbench.com

[Paolo Maldini]

Re: simple problem with delete []

i noticed one line in your code:

>>strcpy(outTex t, inText.c_str()) ;

the length of outText is 5, and also the length of inText is 5, overflow. no
room to store '\0' in outText.
so the calling sequence should be as below:
int main() {
temp = new char[LENGTH];
......
limitNameLength (name, temp, LENGTH-1);
......
delete temp;
......
}


"michael" <spam@begone.ne tдÈëÏûÏ¢ÐÂÎÅ:4 6455386$0$9097$ 5a62ac22@per-qv1-newsreader-01.iinet.net.au ...

Hi All,
>
I have the following:
>
const int LENGTH = 5;
>
void limitNameLength (string inText, char *&outText, int outLength){
if(static_cast< int>(inText.len gth()) outLength){
inText = inText.substr(0 , outLength);
}
strcpy(outText, inText.c_str()) ;
if(static_cast< int>(strlen(out Text)) < outLength){
for(int i = strlen(outText) ; i < outLength; i++){
outText[i] = ' ';
}
}
outText[outLength] = static_cast<cha r>(NULL);
}
>
int main(){
char *temp;
string name = "some long name";
>
temp = new char[LENGTH];
cout << "before : " << name << "\n";
limitNameLength (name, temp, LENGTH);
cout << "after : " << temp << "\n";
>
delete [] temp;
return 0;
}
>
if I comment out the call to limitNameLength the delete [] works ok. If I
don't the delete [] never returns.....
Can anyone tell me why? As far as I can see all I have done is pass the
array to another function to manipulate it a bit then delete it. Why does
delete not work?
>
Thanks for your help
>
Michael
>

[michael]

Re: simple problem with delete []


"Ivan Vecerina" <_INVALID_use_w ebform_@ivan.ve cerina.comwrote in message
news:a5055$4645 5eee$55da15e3$2 8099@news.hispe ed.ch...

"michael" <spam@begone.ne twrote in message
news:46455386$0 $9097$5a62ac22@ per-qv1-newsreader-01.iinet.net.au ...
: Hi All,
:
: I have the following:
:
: const int LENGTH = 5;
:
: void limitNameLength (string inText, char *&outText, int outLength){
You can have char* outText - no need to make it a reference
since the function does not change the pointer address itself.
: if(static_cast< int>(inText.len gth()) outLength){
: inText = inText.substr(0 , outLength);
: }
: strcpy(outText, inText.c_str()) ;
: if(static_cast< int>(strlen(out Text)) < outLength){
: for(int i = strlen(outText) ; i < outLength; i++){
: outText[i] = ' ';
: }
: }
All of the previous can be simply written as:

ummm... no it can't
you will notice that I am padding the output string with spaces so it is
always the same length. strncpy() will not do this for me.

void limitNameLength ( string const& inText
, char *outText, int const outLength)
{
strncpy( outText, inText.c_str(), outLength );
//NB: if outLength<inTex t.size(), there will be no final '\0'
>
: outText[outLength] = static_cast<cha r>(NULL);
why not just: '\0' ?
>
This effectively relies on outText having a length
of outLength+1 !
>
: }
:
: int main(){
: char *temp;
: string name = "some long name";
:
: temp = new char[LENGTH];
: cout << "before : " << name << "\n";
: limitNameLength (name, temp, LENGTH);
: cout << "after : " << temp << "\n";
:
: delete [] temp;
: return 0;
: }
:
: if I comment out the call to limitNameLength the delete [] works ok.
If I
: don't the delete [] never returns.....
: Can anyone tell me why? As far as I can see all I have done is pass
the
: array to another function to manipulate it a bit then delete it. Why
does
: delete not work?
>
When you allocate an array of size LENGTH, the valid indices
are 0 .. LENGTH-1. limitNameLength writes over outText[LENGTH].
>

yeah, thanks for that........cas e of looking but not seeing :-)

The buffer provided to limitNameLength needs to have 1 more character
than the requested maximum length of the string.
If outLength is to be the maximum buffer size, you could change
the last line to:
outText[outLength-1] = '\0';
>
>
>
--
http://ivan.vecerina.com/contact/?subject=NG_POST <- email contact form
Brainbench MVP for C++ <http://www.brainbench.com
>

[Thomas J. Gritzan]

Re: simple problem with delete []

Paolo Maldini wrote:

i noticed one line in your code:

>>strcpy(outTex t, inText.c_str()) ;

the length of outText is 5, and also the length of inText is 5, overflow. no
room to store '\0' in outText.
so the calling sequence should be as below:
int main() {

char*

temp = new char[LENGTH];
......
limitNameLength (name, temp, LENGTH-1);
......
delete temp;

delete[] temp;

......
}

Also, please don't top-post. See my signature.

--
Thomas

http://www.netmeister.org/news/learn2quote.html