I am trying to get the user to input 1-10 and that will select a a number from an array and place it into a variable. here is the code.
the problem is. when I try and add the two numbers (num1 + num2) it says there is a "non-lvalue in assignment".
are my switch statements incorect? can I not do that with an array?
all help is much Appreciated . Thanks in advance.
Code:
do
{
cout << "Enter the first row from column 1 to be summed (1-10)";
cout << endl << endl;
cin >> answer1;
switch(answer1)
{
case '1': a[0][0] = num1;
break;
case '2': a[1][0] = num1;
break;
case '3': a[2][0] = num1;
break;
case '4': a[3][0] = num1;
break;
case '5': a[4][0] = num1;
break;
case '6': a[5][0] = num1;
break;
case '7': a[6][0] = num1;
break;
case '8': a[7][0] = num1;
break;
case '9': a[8][0] = num1;
break;
case '10': a[9][0] = num1;
break;
default : cout << "Invalid input, please select a number 1-10";
cout << endl << endl;
}//end switch for answer 1
cout << "Enter the second row from column 1 to be summed (1-10)";
cout << endl << endl;
cin >> answer2;
switch(answer2)
{
case '1': a[0][0] = num2;
break;
case '2': a[1][0] = num2;
break;
case '3': a[2][0] = num2;
break;
case '4': a[3][0] = num2;
break;
case '5': a[4][0] = num2;
break;
case '6': a[5][0] = num2;
break;
case '7': a[6][0] = num2;
break;
case '8': a[7][0] = num2;
break;
case '9': a[8][0] = num2;
break;
case '10': a[9][0] = num2;
break;
default : cout << "Invalid input, please select a number 1-10";
cout << endl << endl;
}//end switch for answer 2
num1 + num2 = total;
total = a[j][1];
the problem is. when I try and add the two numbers (num1 + num2) it says there is a "non-lvalue in assignment".
are my switch statements incorect? can I not do that with an array?
all help is much Appreciated . Thanks in advance.
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