simple program on execv() function

[martin paul]

Sir please consider the following....
I would like to copy contents from one file (mart1.c) to another file (mart2.c) using execv() function (using command line arguments).....
The command line argument string is "cp mart1.c mart2.c"
Consider the following code..
int main (int argc, char *argv[])
{
char c[]="cp mart1.c mart2.c";
argv[0]=strtok(c," " );
argv[1]=strtok(0," " );
argv[2]=strtok(0," ");
execv("/bin/cp","cp",argv );
}
The contents are not getting copied when I run this code...Is there mistake in the code..Kindly correct the above code...
Thank you..

[Motoma]

I have moved this thread to the C forum. Hopefully you will find help there.

[gpraghuram]

Hi,

int main (int argc, char *argv[])
{
char c[]="cp mart1.c mart2.c";
//argv[0]=strtok(c," " ); //Instead of assigning do strcpy
strcpy(argv[0],strtok(c," " ));
argv[1]=strtok(0," " );
argv[2]=strtok(0," ");
execv("/bin/cp","cp",argv);
}

Replace assignment with strcpy and then try it...that will solve the issue.

Thanks
Raghuram

[martin paul]

Hi,

int main (int argc, char *argv[])
{
char c[]="cp mart1.c mart2.c";
//argv[0]=strtok(c," " ); //Instead of assigning do strcpy
strcpy(argv[0],strtok(c," " ));
argv[1]=strtok(0," " );
argv[2]=strtok(0," ");
execv("/bin/cp","cp",argv);
}

Replace assignment with strcpy and then try it...that will solve the issue.

Thanks
Raghuram

Thank you Sir....
Sir could u please tell me the difference between copying and assigning...
Thank you...