Arrays as arguements

[ilikepython]

Hello, I am having touble passing multidimensiona l arryas as an arguement to a function. This is what I have tried:

void printarray(char array[5][5]){
    for (int x = 0; x < 5; x++){
        for (int y = 0; y < 5; y++){
            cout << array[x][y];}
        cout << endl;}}

int main(){
    char array[5][5];
    printarray(array);
    // rest of program

I've also tried declaring the function like: void printarray(char array[][5])
void printarray(char *array[5][5])
void printarray(char *array[][5])

and calling it like: printarray(&arr ay)
printarray(*arr ay)

and none of those work.

The error message is:

 cannot convert `char (*)[4]' to `char*' for argument `1' to `void printarray(char*)'

Does anybody know what I'm doing wrong?
I'm using Dev C++ on Windows XP.

Thanks in advance.

[ilikepython]

Never mind, sorry guys.
I got it all figuered out.
Don't need help anymore.
Thanks

[rgb]

pass a pointer of the array as an argument.

[JosAH]

pass a pointer of the array as an argument.

That's not needed: arrays are passed as a pointer to their first element in every
calue constant. The first element of a two dimensional is a one dimensional
array so a pointer to it looks like this:

void print(char (*row)[5]) { ... }

Of course for the print function itself there's no way to determine how many
rows the two dimensional matrix has.

kind regards,

Jos