Multi-word #define

[Army1987]

Is there a way to #define a sequence of several identifiers into something
else?
For example, suppose I write:

#include <limits.h>
#ifndef LLONG_MAX /* C89 */
#define LLONG_MAX LONG_MAX
#define LLONG_MIN LONG_MIN
#define ULLONG_MAX ULONG_MAX
#define long_long long
#else /* C99 */
#define long_long long long
#endif

Can I simply write something such as #define (long long) long, so that I
don't need the else branch above, and I don't have to use non-standard
identifiers such as long_long?

--
#include <stdio.h>
#include <stdlib.h>
int main(void) /* Don't try this at home */ {
const size_t dim = 256; int i;
for (i=0; malloc(dim); i++) /*nothing*/ ;
printf("You're done! %zu\n", i*dim);
puts("\n\n--Army1987"); return 0;
}

[Eric Sosman]

Re: Multi-word #define

Army1987 wrote:

Is there a way to #define a sequence of several identifiers into something
else?
For example, suppose I write:
>
#include <limits.h>
#ifndef LLONG_MAX /* C89 */
#define LLONG_MAX LONG_MAX
#define LLONG_MIN LONG_MIN
#define ULLONG_MAX ULONG_MAX
#define long_long long
#else /* C99 */
#define long_long long long
#endif
>
Can I simply write something such as #define (long long) long, so that I
don't need the else branch above, and I don't have to use non-standard
identifiers such as long_long?

No. One identifier <-one macro.

--
Eric Sosman
esosman@acm-dot-org.invalid

[Ben Pfaff]

Re: Multi-word #define

"Army1987" <please.ask@for .itwrites:

Can I simply write something such as #define (long long) long, so that I
don't need the else branch above, and I don't have to use non-standard
identifiers such as long_long?

No, there's no way to do that.
--
Comp-sci PhD expected before end of 2007
Seeking industrial or academic position *outside California* in 2008