having problem with functions

[zaacze]

does anybody knows the answer to this? a function that take in an uppercase character parameter. The function returns the next uppercase character if lett is between 'A' and 'Y'. if let=='Z', the function returns 'A'... i tried to do it but after entering a letter, nothing happens... help pls.. need it so urgently....tha nks a lot!

[Savage]

Hi,

maybe if you could make char whit coresponding ASCII code for each character in depandance of char inputed
and then increase it by one if it is beetwen A and Y or else set to 65 if the
character is Z.

Savage

[zaacze]

thanks for the reply.. i do understand the logic about setting 'Z' to say, 65... but the thing is, i've tried to do it but after the prompt for entering a number, nothing happens..

[gpraghuram]

Hi,
Try this code

int main()
{
	int lnIpChar;
	printf("Enter the charecter\n");
	lnIpChar=getchar();
	printf("%d\n",lnIpChar);
	if(lnIpChar >= 65 && lnIpChar <= 90)
	{
		if(lnIpChar == 90)
		{
			lnIpChar = 64;
		}
		printf("%c\n",++lnIpChar);
	}
	else
	{
		printf("%c\n",lnIpChar);
	}

}

Thanks
Raghuram

[svlsr2000]

Hi,
Try this code

int main()
{
	int lnIpChar;
	printf("Enter the charecter\n");
	lnIpChar=getchar();
	printf("%d\n",lnIpChar);
	if(lnIpChar >= 65 && lnIpChar <= 90)
	{
		if(lnIpChar == 90)
		{
			lnIpChar = 64;
		}
		printf("%c\n",++lnIpChar);
	}
	else
	{
		printf("%c\n",lnIpChar);
	}

}

Thanks
Raghuram

hi zaacze can you post your code to see where you are getting struck up

[zaacze]

hi! the program u've shown is basically the same with what am doing now... the problem is, now after entering a character, nothing happens, it doesn't show anything not unless you would try to run the program agen... that's exactly where i am stuck!...

[gpraghuram]

Hi,
I executed it and i am getting the output properly.
I entered A and then pressed "Enter" key and got the output as B.
I cant make out why its not happeneing for you
Thanks
Raghuram

[zaacze]

anyway, thanks a lot for the help...

[Savage]

Hi,
Try this code

int main()
{
	int lnIpChar;
	printf("Enter the charecter\n");
	lnIpChar=getchar();
	printf("%d\n",lnIpChar);
	if(lnIpChar >= 65 && lnIpChar <= 90)
	{
		if(lnIpChar == 90)
		{
			lnIpChar = 64;
		}
		printf("%c\n",++lnIpChar);
	}
	else
	{
		printf("%c\n",lnIpChar);
	}

}

Thanks
Raghuram

Maybe because your main() is not returning a value.


Savage

[JosAH]

If you're sure that the parameter is an uppercase letter you can simply define
a macro like this:

#define NEXT(U) ((U == 'Z')?'A':(U+1))

kind regards,

Jos