iterating through a set<string> when passed by reference

[Zootal]

The following code will compile. I have one line commented out because it
won't compile. Why can I not do this:

//set<string>::it erator iterator = s->begin();

Why do I have to deference the set when I receive it as a pointer? Is that
just the way we are supposed to do it, or am I missing something?

-------------------------------------------------

#include <iostream>
#include <set>
#include <string>
using namespace std;

typedef set<stringStrin gSet;

void zoot(set<string * s);

int main()
{
set<strings;
s.insert("aaa") ;
s.insert("bbb") ;
zoot( &s );
return 0;
}

void zoot(set<string * s )
{
// This won't compile - why?
//set<string>::it erator iterator = s->begin();

// dereference s, use s1, and it compiles
set<strings1 = *s;
for( set<string>::it erator iterator1 = s1.begin();iter ator1 !=
s1.end();iterat or1++)
{
cout << *iterator1;
}
}

[Ismo Salonen]

Re: iterating through a set&lt;string&g t; when passed by reference

Zootal wrote:

The following code will compile. I have one line commented out because it
won't compile. Why can I not do this:
>
//set<string>::it erator iterator = s->begin();
>
Why do I have to deference the set when I receive it as a pointer? Is that
just the way we are supposed to do it, or am I missing something?
>
-------------------------------------------------
>
#include <iostream>
#include <set>
#include <string>
using namespace std;
>
typedef set<stringStrin gSet;
>
void zoot(set<string * s);
>
int main()
{
set<strings;
s.insert("aaa") ;
s.insert("bbb") ;
zoot( &s );
return 0;
}
>
void zoot(set<string * s )
{
// This won't compile - why?
//set<string>::it erator iterator = s->begin();
>
// dereference s, use s1, and it compiles
set<strings1 = *s;
for( set<string>::it erator iterator1 = s1.begin();iter ator1 !=
s1.end();iterat or1++)
{
cout << *iterator1;
}
}
>
>

What compiler and what error message ?

You could try (*s).begin() , MSVC6 had problems with s-syntax
sometimes, it did not correctly implement templates for obvious reasons.

ismo

[advice.of.deal@gmail.com]

Re: iterating through a set&lt;string&g t; when passed by reference

I use MSVC6 to compile your code. It's OK. There is not any complile
errors. (before compile I and a '}' and then restore the line that you
comment out )




On 3ÔÂ13ÈÕ, ÏÂÎç12ʱ05·Ö, "Zootal" <nousenets...@z ootal.nospam.co mwrote:

The following code will compile. I have one line commented out because it
won't compile. Why can I not do this:
>
//set<string>::it erator iterator = s->begin();
>
Why do I have to deference the set when I receive it as a pointer? Is that
just the way we are supposed to do it, or am I missing something?
>
-------------------------------------------------
>
#include <iostream>
#include <set>
#include <string>
using namespace std;
>
typedef set<stringStrin gSet;
>
void zoot(set<string * s);
>
int main()
{
set<strings;
s.insert("aaa") ;
s.insert("bbb") ;
zoot( &s );
return 0;
>
}
>
void zoot(set<string * s )
{
// This won't compile - why?
//set<string>::it erator iterator = s->begin();
>
// dereference s, use s1, and it compiles
set<strings1 = *s;
for( set<string>::it erator iterator1 = s1.begin();iter ator1 !=
s1.end();iterat or1++)
{
cout << *iterator1;
}
>
>
>
}- Òþ²Ø±»ÒýÓÃÎÄ×Ö -
>
- ÏÔʾÒýÓõÄÎÄ×Ö -

[Cari Elf]

Re: iterating through a set&lt;string&g t; when passed by reference

Have you tried passing the set by reference?

void zoot(set<string & s )
{
set<string>::it erator it;
for (it = s.begin(); it != s.end(); ++it)
{
cout << *it;
}
}

[gethostbyname@gmail.com]

Re: iterating through a set&lt;string&g t; when passed by reference

On 13 mar, 01:05, "Zootal" <nousenets...@z ootal.nospam.co mwrote:

The following code will compile. I have one line commented out because it
won't compile. Why can I not do this:
>
//set<string>::it erator iterator = s->begin();
>
Why do I have to deference the set when I receive it as a pointer? Is that
just the way we are supposed to do it, or am I missing something?
>
-------------------------------------------------
>
#include <iostream>
#include <set>
#include <string>
using namespace std;
>
typedef set<stringStrin gSet;
>
void zoot(set<string * s);
>
int main()
{
set<strings;
s.insert("aaa") ;
s.insert("bbb") ;
zoot( &s );
return 0;
>
}
>
void zoot(set<string * s )
{
// This won't compile - why?
//set<string>::it erator iterator = s->begin();
>
// dereference s, use s1, and it compiles
set<strings1 = *s;
for( set<string>::it erator iterator1 = s1.begin();iter ator1 !=
s1.end();iterat or1++)
{
cout << *iterator1;
}
>
}

It compiles here, VS 2005.

gethostbyname

[Ook]

Re: iterating through a set&lt;string&g t; when passed by reference

>
It compiles here, VS 2005.
>

I'm using VS2003. I tried it on my desktop, and it compiles fine. My
laptop has VS2003 academic version, and it gives an error - I don't
have it with me now so I can't post the actual error, but I can do
that tonight. WTF? Is anyone aware of any differences between the
academic version and the retail version?

[Ook]

Re: iterating through a set&lt;string&g t; when passed by reference

You could try (*s).begin() , MSVC6 had problems with s-syntax

sometimes, it did not correctly implement templates for obvious reasons.
>
ismo

Interesting enough, that fixed another problem I had. I was doing
this:

Item* bb = *iterator;

And using bb because I couldn't figure out how to use the item the
iterator was pointing to, until I figured out I can use (*iterator)
instead. Thanks for the info :)

[Victor Bazarov]

Re: iterating through a set&lt;string&g t; when passed by reference

Ook wrote:

>It compiles here, VS 2005.
>>

>
I'm using VS2003. I tried it on my desktop, and it compiles fine. My
laptop has VS2003 academic version, and it gives an error - I don't
have it with me now so I can't post the actual error, but I can do
that tonight. WTF? Is anyone aware of any differences between the
academic version and the retail version?

People in 'microsoft.publ ic.vc.language' probably are.

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

[Zootal]

Re: iterating through a set&lt;string&g t; when passed by reference


"Zootal" <nousenetspam@z ootal.nospam.co mwrote in message
news:AZ6dnQeW8a uavmvYnZ2dnUVZ_ qSrnZ2d@giganew s.com...

The following code will compile. I have one line commented out because it
won't compile. Why can I not do this:
>
//set<string>::it erator iterator = s->begin();
>

<snip>

So I get home tonight, load the project, and it compiles. I spent an hour
banging my head against the wall, wondering why it would not compile. I'm
loosing it. Microsoft products hate me because I run linux on my server,
that must be it...

[gethostbyname@gmail.com]

Re: iterating through a set&lt;string&g t; when passed by reference

On 13 mar, 22:11, "Zootal" <nousenets...@z ootal.nospam.co mwrote:

"Zootal" <nousenets...@z ootal.nospam.co mwrote in message
>
news:AZ6dnQeW8a uavmvYnZ2dnUVZ_ qSrnZ2d@giganew s.com...The following code will compile. I have one line commented out because it

won't compile. Why can I not do this:

>

//set<string>::it erator iterator = s->begin();

>
<snip>
>
So I get home tonight, load the project, and it compiles. I spent an hour
banging my head against the wall, wondering why it would not compile. I'm
loosing it. Microsoft products hate me because I run linux on my server,
that must be it...

IMHO, if you would like to work with VS, use the 2005 Edition. Or use
gcc on Win :-)

gethostbyname