Obtaining member function/function object's operator() signature

[psujkov@gmail.com]

Hi everybody,

in addition to my previous question, first of all this :

template<typena me F>
void foo(const F& f)
{
std::cout << boost::function _traits<F>::ari ty << std::endl;

}

foo(f);

was a great solution for a free functions, so thanks to everybody for
answers :) but, alas, this is not a solution for both member functions
and function objects : boost::function _traits cannot work with any of
these types. any ideas ?..

best regards, Paul Sujkov

[psujkov@gmail.com]

Re: Obtaining member function/function object's operator() signature

Thanks for anyone trying to workaround this (if there were any) ;)
issue is solved, no answers are needed anymore...

best regards, Paul Sujkov