c language

[sekitoleko]

I have this piece of code,
int i,j,l=0,k=l+4;
l - = k;
j=k+10;
i+=2;
What is the value of i,j,k after the code has been executed.
would i be right to say that k=4;l=3,j=14 and i=1.

[horace1]

I have this piece of code,
int i,j,l=0,k=l+4;
l - = k;
j=k+10;
i+=2;
What is the value of i,j,k after the code has been executed.
would i be right to say that k=4;l=3,j=14 and i=1.

why don't you write a program to try it?

[Motoma]

I have this piece of code,
int i,j,l=0,k=l+4;
l - = k;
j=k+10;
i+=2;
What is the value of i,j,k after the code has been executed.
would i be right to say that k=4;l=3,j=14 and i=1.

No k=4, l=-4, j=14, and i was never assigned.

[willakawill]

No k=4, l=-4, j=14, and i was never assigned.

Not quite true.
i was never defined (or initialized) which means it could contain any amount of garbage contained in the 4 bytes of memory allocated to it. It was then assigned that garbage + 2, the result of which could be anything.

[Gjhoanne]

I have this piece of code,
int i,j,l=0,k=l+4;
l - = k;
j=k+10;
i+=2;
What is the value of i,j,k after the code has been executed.
would i be right to say that k=4;l=3,j=14 and i=1.

what do u think?

[horace1]

what do u think?

int i,j,l=0,k=l+4;

i, j, l and k are defined (name and type declared and storage allocated) and l and k initialised to 0 and 4 respectively. Being local variables i and j are not initialised and their values will be whatever is in the memory locations.

l - = k;

K (value 4) is subtracted from l (value 0) and the result (value -4) assigned to l

j=k+10;

10 is added to k (value 4) and result (value 14) assigned to j

i+=2;

2 is added to i (value ?) and result (value ?) assigned to i

if you are not sure about the results of some expression write a program to try it, e.g.

#include <iostream>
using namespace std;
int main()
{
int i,j,l=0,k=l+4;
l -= k;
j=k+10;
i+=2;
cout << "i="<< i << " j="<<  j << " k="<<  k << " l=" << l << endl;
cin.get();
}