Converting WHILE LOOP into FUNCTIONS

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Hello everyone!:) i need your help again..i got there a code of a while loop program and our prof let us convert it into functions. can anyone help me please. It must be converted into 3 types.

1. void only
2. void but with parameter
3. w/out void but with return value

Here's the code:

1 #include <stdio.h>
2 #include <iostream.h>
3 #include <conio.h>
4
5 int main(void)
6
7 {
8
9 int i, j;
10 i=0;
11 while (i<=4) {
12 j=0;
13 while (j<=4) {
14 j++;
15 }
16 i++;
17 }
18 i++;
19 printf("%d", i*j);
20
21 return 0;
22 }

I run this program already and the output is 30. I really appreciate your help everyone. Thank you very much

[willakawill]

Hello everyone!:) i need your help again..i got there a code of a while loop program and our prof let us convert it into functions. can anyone help me please. It must be converted into 3 types.

1. void only
2. void but with parameter
3. w/out void but with return value

Here's the code:

1 #include <stdio.h>
2 #include <iostream.h>
3 #include <conio.h>
4
5 int main(void)
6
7 {
8
9 int i, j;
10 i=0;
11 while (i<=4) {
12 j=0;
13 while (j<=4) {
14 j++;
15 }
16 i++;
17 }
18 i++;
19 printf("%d", i*j);
20
21 return 0;
22 }

I run this program already and the output is 30. I really appreciate your help everyone. Thank you very much

An example of one of these would be to create a function that returns the product of i and j

int product(int i, int j) {
   return i * j;
}

and then use this in your code:

printf("%d", product(i, j));

Good luck

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Thanks for that help madam :) but how about for the void only and void with parameter? got any ideas?

[willakawill]

Thanks for that help madam :) but how about for the void only and void with parameter? got any ideas?

A void only function takes no parameters and returns nothing

void say_hi(void) {
   printf("%s", "Hello World");
}

and is used by

say_hi();

void with parameters:

void say_something(char *message) {
   printf("%s", message);
}

and is used:

say_something("Hello World");

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maam villa, i tried to create a void with parameter code but it says syntax error and our prof told me that it's not correct. my code is below..

#include <stdio.h>

void prn_value(int x, int y);

int main(void)

{
int i, j;
i=0;
while (i<=4) {
j=0;
while (j<=4) {
j++;
}
i++;
}
i++;
prn_value (i,j);
return 0;
}

void prn_value(int x, int y)

{

int value=i*j;
printf("The product is %d", value);

}

what's wrong with my code boss?

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i created another code...

include <iostream.h>
#include <conio.h>

int product (int i, int j);

int main(void)

{

product (i, j);


}

int product (int i, int j)

{


i=0;
while (i<=4) {
j=0;
while (j<=4) {
j++;
}
i++;
}
i++;
cout << i*j;

return i * j;
}

it says declaration syntax error on int main(void).

can somebody help me..

thanks a lot..

[horace1]

the formal parameters to

void prn_value(int x, int y)
{
	int value=i*j;
	printf("The product is %d", value);
}

are x and y but you use i and j in the code

be consistent either use i &j or x and y throughout the function e.g.

void prn_value(int x, int y)
{
	int value=x*y;  // ** replace i and j with x and y
	printf("The product is %d", value);
}

[khajeddin]

hi:you must defne all you variables in the begining of mail function.and then send whatever you want to Product function.

include <iostream.h>
#include <conio.h>

int product (int i, int j);

int main(void)

{
/*you must define some variables here*/
product (i, j);


}

int product (int i, int j)

{


i=0;
while (i<=4) {
j=0;
while (j<=4) {
j++;
}
i++;
}
i++;
cout << i*j;

return i * j;
}

[khajeddin]

on the other hand you can write a Only Void function with defining two Global parameter in the begining of program

#include<stdio.h>
int i;
int j;
void product(void);
int main()
  {....
   product(); 
   ....}

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#include <iostream.h>
#include <conio.h>

int product (int x, int y);

int main(void)

{
	clrscr();
	int a, b, total;
	total=product(a,b);
	printf("The output is %d", total);
	getch();
	return 0;


}

int product (int x, int y)

{

	x=0;
	while (x<=4) {
	   y=0;
	   while (y<=4) {
	      y++;
	   }
	   x++;
	}
	x++;

	return x * y;


}

so this is the right one, right???

[horace1]

not sure what your program is suposed to do, e.g. you pass in parameters a and b but without any values, the values are set up inside the function - why pass in parameters? you don't need them.

e.g. you could define the variables inside the function so

#include <iostream.h>

int product (void);

int main(void)

{
	int total;
	total=product();
	printf("The output is %d", total);
	getchar();
	return 0;
}

int product (void)

{
    int x, y;
	x=0;
	while (x<=4) {
	   y=0;
	   while (y<=4) {
	      y++;
	   }
	   x++;
	}
	x++;
	return x * y;
}

note that it is not recommended to use header file <conio.h>, clrscr() and getch(). They are not standard C/C++ and are not available with many compilers.

It is also not recommended to use

#include <iostream.h>

which is a deprecated header. Modern compilers use

#include <iostream>
using namespace std;

however, if you have an old compiler (such as Turbo C V3.0) it will not support this.

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And here's one for the Only Void code...

#include <iostream.h>
#include <stdlib.h>

int i, j;

void product (void);

int main(void)
{
system("CLS");
product();
}

void product (void)

{
i=0;
while (i<=4) {
j=0;
while (j<=4) {
j++;
}
i++;
}
i++;
cout << i*j << endl;
}

are they all correct boss?

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#include <iostream.h>

int product (void);

int main(void)

{
int total;
total=product() ;
printf("The output is %d", total);
getchar();
return 0;
}

int product (void)

{
int x, y;
x=0;
while (x<=4) {
y=0;
while (y<=4) {
y++;
}
x++;
}
x++;
return x * y;
}


ic.. so what's the difference of the code similar to the one i posted before? it also gave me the same output even if i have

int a, b, total;
total=product (a,b)

inside the main body and (int x, int y) parameter upon declaring the function.

can you explain it to me sir..thank you.