C++ Output

[melaghil]

Hi all,

I'm really having a problem, and it is in the output results.

There are basically two loops. I want to set the first loop to be in the ouptput in the second loop.

Here is my code:

//first loop
for (int c = 0; c < wordcount; c++) {
for (int g =1; g < wordcount; g++) {
if (word[c] == word[g] ) {
cout << Dictionary[g-1] << endl;
}
}
}

//second loop
for (int i = 1 , L = 0; i <= wordcount , L <= wordcount; i++ , L++) {
cout << word[i] << " " << Dictionary[L] << " " << endl;
}

that is to be like this:

for (int i = 1 , L = 0; i <= wordcount , L <= wordcount; i++ , L++) {
cout << word[i] << " " << Dictionary[L] << " " <<
for (int c = 0; c < wordcount; c++) {
for (int g =1; g < wordcount; g++) {
if (word[c] == word[g] ) {
cout << Dictionary[g-1] << endl;
}
}
}
<< endl;
}


I tried to include them in a while loop but its not working.
hope one of you guys will help me out.

Thanks in advance.

[kirubanantham]

Hai Melaghil,
I dont understand any thing from your code. please can you clearly explain your problem.

Cheers
K.Kiruba.

[melaghil]

Thanks for you reply, and sorry for my uncleared wiritng as i was in a rush.

here is wt the program does.
Part 1:
You have a list of the dictionary words stored in a text file. the program takes the words line by line, and sort them in alpahpetical order (anagram),
so if we have a word called lemon then the output is in this form.

elmno lemon

and thats wt is done by this loop

for (int i = 1 , L = 0; i <= wordcount , L <= wordcount; i++ , L++) {
cout << anagram[i] << " " << Dictionary[L] << " " << endl;
}

Part 2:

sometimes a word like monel have the same anagram as the word lemon, if this case happened then the output should be like this

elmno lemon monel


the problem i have is, i have done part 1, and i want to combine both parts

here is the seocnd loop that i want to combined with the first one:

for (int c = 0; c < wordcount; c++) {
for (int g =1; g < wordcount; g++) {
if (word[c] == word[g] ) {
cout << Dictionary[g-1] << endl;
}
}
}

Hope will clear it more.

Thanks again

[mohsin]

hi
well would u like to tell me that what do u want from this code i mean i m still doubtfull about your code
thanks