delete an alphabet

[xx1level1xx]

#

Write a function named deleteS that accepts one character pointer as a parameter and returns no value. The parameter is a C string. This function must remove all of the upper and lower case 's' letters from the string. The resulting string must be a valid C string.

Your function must declare no more than one local variable in addition to the parameter; that additional variable must be of a pointer type. Your function may not use any square brackets.

int main()
{
char msg[50] = "She'll be a massless princess.";
deleteS(msg);
cout << msg; // prints he'll be a male prince.
}


Can anyone give me some hints on this? Thx

this is how my function gonna look like.. I think...
void deleteS(const char* str, char alpha)

and alpha is gonna be S or s

[xx1level1xx]

ooop it should be void deleteS(char* str)

[xx1level1xx]

I m a neophyte and this is my nonworking code:


[void deleteS(char *str)
{
char* source= str;

while(*source!= 0)
{
*source=*str;
if (str!="S" ||str!="s")
{

source++;
str++;
}
else if (str=="S"|| str== "s")
{
str++;
}
}
}

[sivadhas2006]

Hi,

You can also do like this.

#include <iostream>

using namespace std;

void deleteS(char * a_pszInput, char *a_pszOutput)
{
   char
      chTemp = '\0';;

   while(*a_pszInput !=0) 
   {      
      chTemp = *a_pszInput;
      if (chTemp != 'S' && chTemp!= 's')
      { 
         *a_pszOutput = *a_pszInput;
         a_pszOutput++;
      }
      a_pszInput++;
   }
}


int main()
{
   char 
      szMsg[50] = "She'll be a massless princess.",
      szResult[50] = "\0";

   deleteS(szMsg, szResult);
   cout << szResult; // prints he'll be a male prince.
   return 0;
}

Regards,
M.Sivadhas.