override function operator question

[abcpp]

Please help:

class B {
public:
void operator()(){ cout<<"in B()"<<endl;}
};

class D : public B {
public:
void operator()() {
B:: (); // compiler would error: expected unqualified-id before ‘(’ token
cout<<"in D()"<<endl;
}
};

How do I invoke base class function operator from derived class function operator? Thanks

[Banfa]

Replace

 B:: (); // compiler would error: expected unqualified-id before ‘(’ token

with

 B::operator()();

[sivadhas2006]

Please help:

class B {
public:
void operator()(){ cout<<"in B()"<<endl;}
};

class D : public B {
public:
void operator()() {
B:: (); // compiler would error: expected unqualified-id before ‘(’ token
cout<<"in D()"<<endl;
}
};

How do I invoke base class function operator from derived class function operator? Thanks

Hi,

I used different operator to make it work.

class B 
{
   public:

      void operator+ ()
      { 
         cout<<"in B()"<<endl;
      }
};

class D : public B 
{
   public:

      void operator +() 
      { 
         B::operator +(); 
         cout<<"in D()"<<endl;
      }
};

Regards,
M.Sivadhas.

[sivadhas2006]

Replace

 B:: (); // compiler would error: expected unqualified-id before ‘(’ token

with

 B::operator()();

Hi,

I tried

 B::operator()();

That also working.

Regards,
M.Sivadhas.

[abcpp]

Replace

 B:: (); // compiler would error: expected unqualified-id before ‘(’ token

with

 B::operator()();

Thank you so much!!!