boost thread example

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  • Gary Wessle

    #1

    boost thread example


    Hi

    given the Boost thread example here


    the code below attempts to run the example
    thread while giving the user a prompt for data input.
    I am failing to get the prompt while the thread is running, what am I
    doing wrong?

    thanks

    *************** *************** *************** *************** ****
    #include <boost/thread/thread.hpp>
    #include <boost/thread/xtime.hpp>
    #include <iostream>
    using namespace std;

    struct thread_alarm
    {
    thread_alarm(in t secs) : m_secs(secs) { }
    void operator()()
    {
    boost::xtime xt;
    boost::xtime_ge t(&xt, boost::TIME_UTC );
    xt.sec += m_secs;

    boost::thread:: sleep(xt);

    std::cout << "alarm sounded..." << std::endl;
    }

    int m_secs;
    };

    int main(){
    int secs = 5;
    std::cout << "setting alarm for 5 seconds..." << std::endl;
    for( ;; ) {
    cout << "type a number please:" << endl;
    int opt;
    cin >opt;
    switch( opt ) {
    case ( 1 ): {
    thread_alarm alarm(secs);
    boost::thread thrd(alarm);
    thrd.join();
    break;
    }
    case (99 ): cout << "Exiting ...\n"; break;
    default: cout << "you typed " << opt << endl;
    }
    }
    }
  • Alf P. Steinbach

    #2
    Re: boost thread example

    * Gary Wessle:
    Hi
    >
    given the Boost thread example here

    >
    the code below attempts to run the example
    thread while giving the user a prompt for data input.
    I am failing to get the prompt while the thread is running, what am I
    doing wrong?
    >
    thanks
    >
    *************** *************** *************** *************** ****
    #include <boost/thread/thread.hpp>
    #include <boost/thread/xtime.hpp>
    #include <iostream>
    using namespace std;
    >
    struct thread_alarm
    {
    thread_alarm(in t secs) : m_secs(secs) { }
    void operator()()
    {
    boost::xtime xt;
    boost::xtime_ge t(&xt, boost::TIME_UTC );
    xt.sec += m_secs;
    >
    boost::thread:: sleep(xt);
    >
    std::cout << "alarm sounded..." << std::endl;
    }
    >
    int m_secs;
    };
    >
    int main(){
    int secs = 5;
    std::cout << "setting alarm for 5 seconds..." << std::endl;
    for( ;; ) {
    cout << "type a number please:" << endl;
    int opt;
    cin >opt;
    switch( opt ) {
    case ( 1 ): {
    thread_alarm alarm(secs);
    boost::thread thrd(alarm);
    thrd.join();
    break;
    }
    case (99 ): cout << "Exiting ...\n"; break;
    default: cout << "you typed " << opt << endl;
    }
    }
    }
    The code above says to wait for the thread to finish before going on
    with issuing the next prompt. From your description it seems the
    program is doing exactly what the code says it should do. Btw., beware
    of doing unsynchronized i/o in threads.

    --
    A: Because it messes up the order in which people normally read text.
    Q: Why is it such a bad thing?
    A: Top-posting.
    Q: What is the most annoying thing on usenet and in e-mail?

    Comment

    • Gary Wessle

      #3
      Re: boost thread example

      "Alf P. Steinbach" <alfps@start.no writes:
      * Gary Wessle:
      Hi
      given the Boost thread example here

      the code below attempts to run the example
      thread while giving the user a prompt for data input. I am failing
      to get the prompt while the thread is running, what am I
      doing wrong?
      thanks
      *************** *************** *************** *************** ****
      #include <boost/thread/thread.hpp>
      #include <boost/thread/xtime.hpp>
      #include <iostream>
      using namespace std;
      struct thread_alarm
      {
      thread_alarm(in t secs) : m_secs(secs) { }
      void operator()()
      {
      boost::xtime xt;
      boost::xtime_ge t(&xt, boost::TIME_UTC );
      xt.sec += m_secs;
      boost::thread:: sleep(xt);
      std::cout << "alarm sounded..." << std::endl;
      }
      int m_secs;
      };
      int main(){
      int secs = 5;
      std::cout << "setting alarm for 5 seconds..." << std::endl;
      for( ;; ) {
      cout << "type a number please:" << endl;
      int opt;
      cin >opt;
      switch( opt ) {
      case ( 1 ): {
      thread_alarm alarm(secs);
      boost::thread thrd(alarm);
      thrd.join();
      break;
      }
      case (99 ): cout << "Exiting ...\n"; break;
      default: cout << "you typed " << opt << endl;
      }
      }
      }
      >
      The code above says to wait for the thread to finish before going on
      with issuing the next prompt. From your description it seems the
      program is doing exactly what the code says it should do. Btw.,
      beware of doing unsynchronized i/o in threads.
      I need the code to issue the next prompt without waiting for the
      thread to finish so that the user can select another "opt" while the
      first thread job is still going.

      Comment

      • Gary Wessle

        #4
        Re: boost thread example

        "Alf P. Steinbach" <alfps@start.no writes:
        * Gary Wessle:
        Hi
        given the Boost thread example here

        the code below attempts to run the example
        thread while giving the user a prompt for data input. I am failing
        to get the prompt while the thread is running, what am I
        doing wrong?
        thanks
        *************** *************** *************** *************** ****
        #include <boost/thread/thread.hpp>
        #include <boost/thread/xtime.hpp>
        #include <iostream>
        using namespace std;
        struct thread_alarm
        {
        thread_alarm(in t secs) : m_secs(secs) { }
        void operator()()
        {
        boost::xtime xt;
        boost::xtime_ge t(&xt, boost::TIME_UTC );
        xt.sec += m_secs;
        boost::thread:: sleep(xt);
        std::cout << "alarm sounded..." << std::endl;
        }
        int m_secs;
        };
        int main(){
        int secs = 5;
        std::cout << "setting alarm for 5 seconds..." << std::endl;
        for( ;; ) {
        cout << "type a number please:" << endl;
        int opt;
        cin >opt;
        switch( opt ) {
        case ( 1 ): {
        thread_alarm alarm(secs);
        boost::thread thrd(alarm);
        thrd.join();
        break;
        }
        case (99 ): cout << "Exiting ...\n"; break;
        default: cout << "you typed " << opt << endl;
        }
        }
        }
        >
        The code above says to wait for the thread to finish before going on
        with issuing the next prompt. From your description it seems the
        program is doing exactly what the code says it should do. Btw.,
        beware of doing unsynchronized i/o in threads.
        >
        if I comment out the line
        thrd.join();
        it gives me the desired effect, is that the correct way to do it?

        Comment

        • dasjotre

          #5
          Re: boost thread example


          Gary Wessle wrote:
          Hi
          struct thread_alarm
          {
          thread_alarm(in t secs) : m_secs(secs) { }
          void operator()()
          {
          boost::xtime xt;
          boost::xtime_ge t(&xt, boost::TIME_UTC );
          xt.sec += m_secs;
          >
          boost::thread:: sleep(xt);
          cout is not synchronized, it might
          overlap with main thread's output

          <snip>
          std::cout << "alarm sounded..." << std::endl;
          }
          <snip>
          switch( opt ) {
          case ( 1 ): {
          thread_alarm alarm(secs);
          boost::thread thrd(alarm);
          join will wait till thrd terminates, that doesn't seem
          to be what you want
          thrd.join();
          break;
          }
          case (99 ): cout << "Exiting ...\n"; break;
          default: cout << "you typed " << opt << endl;
          I believe you want the alarm to sound if the user
          takes more than 5 seconds to type

          In that case you will need to cancel the alarm
          here. your current implementation of thread_alarm
          doesn't provide such functionality

          maybe looping around a flag for a fraction
          of alarm time and then changing the flag
          to exit the loop would do.

          general idea:

          struct thread_alarm
          {
          bool loop_;
          thread_alarm(in t secs) : m_secs(secs) , loop_(true){ }

          void cancel(){ loop_= false; }

          void operator()()
          {
          while(loop_ && m_secs)
          {
          boost::xtime xt;
          boost::xtime_ge t(&xt, boost::TIME_UTC );
          // sleep a second at a time
          xt.sec += 1;
          --m_secs;
          boost::thread:: sleep(xt);
          }
          if(loop_)
          std::cout << "alarm sounded..." << std::endl;
          }

          int m_secs;
          };

          Comment

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