string extraction

[Gary Wessle]

Hi
given a coma delimited string "abc.,def.,ghj. ,my name is", I need to
get the output

//output
abc.
def.
jhj.
my name is


here is how I did it but it is messy. I hope someone came up with a
cleaner version.

thank you

short Conn_task::prin t_smi(const string& s){
short itm = 0;
int from =0;
int sz = 0;
while( from <= s.rfind(",") ){
if( sz = s.find(",", from) )
cout << "[" << itm << "] " << s.substr(from, sz-from) << endl;
from =sz+1;
++itm;
}
cout << itm << s.substr(from, s.length()-from) << endl;
}

[rep_movsd]

Re: string extraction


Gary Wessle wrote:

Hi
given a coma delimited string "abc.,def.,ghj. ,my name is", I need to
get the output
>
//output
abc.
def.
jhj.
my name is
>

boost::tokenize r is ideal for this.
Look at the boost library, its almost part of the C++ standard and has
all the most important reinvented wheels.

Regards
Vivek

[ondra.holub]

Re: string extraction

Here are two versions. First one is slightly modified your version, the
second is with iterato. You can use any of them which you like:

#include <string>
#include <iostream>

short SplitString(con st std::string& s, char split_char = ',')
{
short itm = 0;
std::string::si ze_type from = 0;

for (;;)
{
std::string::si ze_type pos = s.find(split_ch ar, from);
std::cout << "[" << itm << "] ";

if (pos == std::string::np os)
{
std::cout << s.substr(from) << "\n";
return itm;
}

std::cout << s.substr(from, pos - from) << "\n";
from = pos + 1;
++itm;
}
}

short SplitString2(co nst std::string& s, char split_char = ',')
{
short itm = 0;

std::cout << "[0] ";
for (std::string::c onst_iterator pos = s.begin(); pos != s.end();
++pos)
{
if (*pos == split_char)
std::cout << "\n[" << ++itm << "] ";
else
std::cout << *pos;
}

std::cout << "\n";
return itm;
}

int main()
{
std::string s("abc.,def.,gh j.,my name is");

std::cout << SplitString(s) << "\n";
std::cout << "---------\n";
std::cout << SplitString2(s) << "\n";
}

[dragan.jovev@gmail.com]

Re: string extraction

Why not use strtok from string.h? This example shows exactly what you
want to achieve:

http://www.cplusplus.com/ref/cstring/strtok.html

Best reguards,
Dragan

On Nov 14, 11:35 am, Gary Wessle <phd...@yahoo.c omwrote:

Hi
given a coma delimited string "abc.,def.,ghj. ,my name is", I need to
get the output
>
//output
abc.
def.
jhj.
my name is
>
here is how I did it but it is messy. I hope someone came up with a
cleaner version.
>
thank you
>
short Conn_task::prin t_smi(const string& s){
short itm = 0;
int from =0;
int sz = 0;
while( from <= s.rfind(",") ){
if( sz = s.find(",", from) )
cout << "[" << itm << "] " << s.substr(from, sz-from) << endl;
from =sz+1;
++itm;
}
cout << itm << s.substr(from, s.length()-from) << endl;
}

[terminator]

Re: string extraction



On Nov 14, 1:59 pm, "ondra.holu b" <ondra.ho...@po st.czwrote:

Here are two versions. First one is slightly modified your version, the
second is with iterato. You can use any of them which you like:
>
#include <string>
#include <iostream>
>
short SplitString(con st std::string& s, char split_char = ',')
{
short itm = 0;
std::string::si ze_type from = 0;
>
for (;;)
{
std::string::si ze_type pos = s.find(split_ch ar, from);
std::cout << "[" << itm << "] ";
>
if (pos == std::string::np os)
{
std::cout << s.substr(from) << "\n";
return itm;
}
>
std::cout << s.substr(from, pos - from) << "\n";
from = pos + 1;
++itm;
}
>
}short SplitString2(co nst std::string& s, char split_char = ',')
{
short itm = 0;
>
std::cout << "[0] ";
for (std::string::c onst_iterator pos = s.begin(); pos != s.end();
++pos)
{
if (*pos == split_char)
std::cout << "\n[" << ++itm << "] ";
else
std::cout << *pos;
}
>
std::cout << "\n";
return itm;
>
}int main()
{
std::string s("abc.,def.,gh j.,my name is");
>
std::cout << SplitString(s) << "\n";
std::cout << "---------\n";
std::cout << SplitString2(s) << "\n";
>
>
>
}- Hide quoted text -- Show quoted text -

is it not possible to replace comas in the original string with zeros
and then sending it to 'cout'?

[ondra.holub]

Re: string extraction

Yes, it is definitely possible (I would suggest to replace it with '\n'
character to get required output) as long as you can modify (and
destroy) content of string. Then it is simillar to use of strtok.

[BobR]

Re: string extraction


Gary Wessle wrote in message ...

>
>Hi
>given a coma delimited string "abc.,def.,ghj. ,my name is", I need to
>get the output
>
>//output
>abc.
>def.
>jhj.
>my name is
>
>here is how I did it but it is messy. I hope someone came up with a
>cleaner version.
>thank you
>
>short Conn_task::prin t_smi(const string& s){
short itm = 0;
int from =0;
int sz = 0;
while( from <= s.rfind(",") ){
if( sz = s.find(",", from) )
cout << "[" << itm << "] " << s.substr(from, sz-from) << endl;
from =sz+1;
++itm;
}
cout << itm << s.substr(from, s.length()-from) << endl;
}

#include <iostream>
#include <ostream>
#include <sstream>

void SplitPrint( std::istream &in, std::ostream &out){
std::string line;
while( std::getline( in, line, ',' ) ){
out << line << std::endl;
}
return;
} // SplitPrint(istr eam&, ostream&)

int main() // or function
{
std::cout<<"--- SplitPrint test"<<std::end l;
// std::string TheLine( "abc.,def.,ghj. ,my name is" );
// std::istringstr eam sis( TheLine );
// SplitPrint( sis, std::cout );
// std::ofstream sofs("MyFile.tx t");
// SplitPrint( sis, sofs );

std::istringstr eam sis( "abc.,def.,ghj. ,my name is" );
std::ostringstr eam sos;
SplitPrint( sis, sos );
std::cout<<sos. str()<<std::end l;
std::cout<<"--- SplitPrint test end"<<std::endl ;
}

/* --- SplitPrint test
abc.
def.
ghj.
my name is
--- SplitPrint test end
*/

Better?
--
Bob R
POVrookie

[BobR]

Re: string extraction


BobR wrote in message ...

>
>#include <iostream>
>#include <ostream>
>#include <sstream>
>

void SplitPrint( std::istream &in, std::ostream &out){
//std::string line;
//while( std::getline(in , line, ',') ){
// out << line << std::endl;
// }

for( std::string line; std::getline( in, line, ',' ); ){
out << line << std::endl;
}

return;
} // SplitPrint(istr eam&, ostream&)

--
Bob R
POVrookie