I would be thankful for any help!!

[cNoob]

I need to write a program to find the sum, sum of squares, sum of the cubes, and sum of a certain series shown below for the first n integers, begining with 1 and ending with n = 100.

Summing the first 100 natural numbers:

n(n+1)
1 + 2 + 3 + ..... + n = ----------
2

Sum of squares of the first 100 natural numbers:

n(n+1)(2n+1)
1² + 2² + 3² + ……. n² = -------------------
6

Sum of cubes of the first 100 natural numbers:

n² (n + 1)²
1³ + 2³ + 3³ + ……. + n³ = --------------
4

Another series:

1 1 1 1 n
------- + ------- + ---------- + .......... ---------- = ------
(1 * 2) (2 * 3) (3 * 4) n*(n+1) n +1

Since all of these series involve summing the same number of terms, do all of the summing inside ONE(1) loop. Compute the formats outside the loop. Use n as a variable in the formulas; do not replace it with 100, because the formulas work for any n and the program should be flexible enough to easily change the number of terms.

[horace1]

implement the program one section at a time, i.e. first Summing the first 100 natural numbers:

1 + 2 + 3 + ..... + n = n(n+1) / 2

an algorithm is

sum=0
for i=1 to 100 
    sum = sum + i
print sum

when that is working add the code for the next section, etc

do you also have to prove the sum = n(n+1) / 2

[cNoob]

implement the program one section at a time, i.e. first Summing the first 100 natural numbers:

1 + 2 + 3 + ..... + n = n(n+1) / 2

an algorithm is

sum=0
for i=1 to 100 
    sum = sum + i
print sum

when that is working add the code for the next section, etc

do you also have to prove the sum = n(n+1) / 2

No I dont hve to......... But im So lost please help :(