C++ Translate English Sentence to Pig Latin

[ahoway]

I am having problems entering a sentence for translating into pig latin. It is set up now to read the entire sentence as one word. I would like to know how to look at each word in the sentence so that each word is translated to Pig latin seperately. Attached is my code: Thank you for your time.

the out put for hello world comes out :ello worldhay
I want it to say: ellohay orldway

// testpig.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;



bool isVowel(char ch);
string rotate(string pStr);
string pigLatinString( string pStr);

int main ()
{

const int LENGTH = 100;
char str [LENGTH];



string word, result;

cout << "Enter a string or, blank to exit." <<endl;
cout << "The program will output the words in Pig Latin."<<endl;
cin.getline(str ,LENGTH);
cout<<endl;

cout << "The pig Latin form of " << str <<" is:\n"<< pigLatinString( str) << endl;

return 0;
/* Process the input line word by word */



};









bool isVowel(char ch)
{
switch (ch)
{
case 'A': case 'E':
case 'I': case 'O':
case 'U':
case 'a': case 'e':
case 'i': case 'o':
case 'u':
return true;
default: return false;
};
}//end isVowel

string rotate(string pStr)

{
string::size_ty pe len=pStr.length ();

string rStr;

rStr=pStr.subst r(1,len-1)+pStr[0];////

return rStr;
}

string pigLatinString( string pStr)

{
string::size_ty pe len;

bool foundVowel;

string::size_ty pe counter;

if (isVowel(pStr[0]))

pStr=pStr+"way" ;

else
{//didn't start with a vowel

pStr = pStr + "";
pStr=rotate(pSt r);
len=pStr.length ();
foundVowel=fals e;

for (counter = 1; counter<len-1; counter++)

if (isVowel(pStr[0]))

{
foundVowel=true ;
break;
}

else

pStr=rotate(pSt r);

if (!foundVowel)

pStr=pStr.subst r(1,len)+"way";

else

pStr = pStr + "ay";
}
return pStr;

}

[sicarie]

I am having problems entering a sentence for translating into pig latin. It is set up now to read the entire sentence as one word. I would like to know how to look at each word in the sentence so that each word is translated to Pig latin seperately. Attached is my code: Thank you for your time.

Check out the C++ function strtok(). I think you can use that to separate out the words, as long as you know the delimiters that will be separating them (like spaces).

[manontheedge]

you can read it in as characters, and signal the end of a word every time it sees a space...that's one way to do it...by avoid strings entirely.

[ahoway]

do either of you know where I get a tutorial on this? My book is not very clear and none of my professors example programs show this. Thanks

[sicarie]

do either of you know where I get a tutorial on this? My book is not very clear and none of my professors example programs show this. Thanks

Strtok:

http://www.cplusplus.com/ref/cstring/strtok.html

For manontheedge's method, it's less of something there would be a tutorial on, you would create a loop that accepted a char, and test it against the value for a 'space', and then did whatever else you wanted.

[susheelam]

Strtok:

http://www.cplusplus.com/ref/cstring/strtok.html

For manontheedge's method, it's less of something there would be a tutorial on, you would create a loop that accepted a char, and test it against the value for a 'space', and then did whatever else you wanted.

Read the whole string the way u have done in ur program.
then extract out each word till u find a space
copy the word to another string from subscript 1 , and concatenate 0th subscript and "way"
continue dor the whole length of the string

[ahoway]

I have solved the first problem, now I need help with...

1.Program repeats until user enters a null string
2.Prompts the user to enter a string or just return to terminate

here is my new code: Thank you in advance!
#include "stdafx.h"
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;



bool isVowel(char ch);
string rotate(string pStr);
string pigLatinString( string pStr);

int main ()
{

string word,line;

cout << "Enter a string or, blank to exit." <<endl;
cout << "The program will output the words in Pig Latin."<<endl;
getline(cin, line);


cout << "The pig Latin form of " << line <<" is:\n";




/* Process the input line word by word */


while ( line.length() != 0)
{
//cout << "==> Enter line of text or enter return to stop input\n";




int lineLen = line.length();
nt wordLen = line.find(' ');
if (wordLen > 0)
{
word = line.substr(0,w ordLen);
line = line.substr(wor dLen+1);

cout << pigLatinString( word) << " ";
}
else
{
cout << pigLatinString( line) <<"\n ";

line = "";
}
}


return 0;
};



////////////////////////////////////////////////////////these are words starting with a vowel
bool isVowel(char ch)
{
switch (ch)
{
case 'A': case 'E': case 'I': case 'O':case 'U':
case 'a': case 'e':case 'i': case 'o': case 'u':
return true;
default: return false;
};
}///////////////////////////////////////////////////////////////end isVowel

string rotate(string pStr)

{
string::size_ty pe len=pStr.length ();

string rStr;

rStr=pStr.subst r(1,len-1)+pStr[0];

return rStr;
}

string pigLatinString( string pStr)

{
string::size_ty pe len;

bool foundVowel;

string::size_ty pe counter;

if (isVowel(pStr[0]))

pStr=pStr+"way" ;

else
{//These are words that didn't start with a vowel



len=pStr.length ();
foundVowel=fals e;



if (isVowel(pStr[0]))

{
foundVowel=true ;
}

else

pStr=rotate(pSt r);

if (!foundVowel)

pStr=pStr.subst r(0,len)+"way";

else

pStr = pStr + "ay";
}
return pStr;

}

[sicarie]

I have solved the first problem, now I need help with...

1.Program repeats until user enters a null string
2.Prompts the user to enter a string or just return to terminate

here is my new code: Thank you in advance!
#include "stdafx.h"
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;



bool isVowel(char ch);
string rotate(string pStr);
string pigLatinString( string pStr);

int main ()
{

string word,line;

cout << "Enter a string or, blank to exit." <<endl;
cout << "The program will output the words in Pig Latin."<<endl;
getline(cin, line);


cout << "The pig Latin form of " << line <<" is:\n";




/* Process the input line word by word */


while ( line.length() != 0)
{
//cout << "==> Enter line of text or enter return to stop input\n";




int lineLen = line.length();
nt wordLen = line.find(' ');
if (wordLen > 0)
{
word = line.substr(0,w ordLen);
line = line.substr(wor dLen+1);

cout << pigLatinString( word) << " ";
}
else
{
cout << pigLatinString( line) <<"\n ";

line = "";
}
}


return 0;
};



////////////////////////////////////////////////////////these are words starting with a vowel
bool isVowel(char ch)
{
switch (ch)
{
case 'A': case 'E': case 'I': case 'O':case 'U':
case 'a': case 'e':case 'i': case 'o': case 'u':
return true;
default: return false;
};
}///////////////////////////////////////////////////////////////end isVowel

string rotate(string pStr)

{
string::size_ty pe len=pStr.length ();

string rStr;

rStr=pStr.subst r(1,len-1)+pStr[0];

return rStr;
}

string pigLatinString( string pStr)

{
string::size_ty pe len;

bool foundVowel;

string::size_ty pe counter;

if (isVowel(pStr[0]))

pStr=pStr+"way" ;

else
{//These are words that didn't start with a vowel



len=pStr.length ();
foundVowel=fals e;



if (isVowel(pStr[0]))

{
foundVowel=true ;
}

else

pStr=rotate(pSt r);

if (!foundVowel)

pStr=pStr.subst r(0,len)+"way";

else

pStr = pStr + "ay";
}
return pStr;

}

I think your best bet is a while loop.

[ahoway]

Now I can get the loop to work, but my English to pig latin is gone?
// testpig.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <iostream>
#include <string>
#include <cstdlib>
#include <cctype>
using namespace std;



bool isVowel(char ch);
string rotate(string pStr);
string pigLatinString( string pStr);

int main ()
{

string word,line;

cout << "Enter a string or, blank to exit." <<endl;
cout << "The program will output the words in Pig Latin."<<endl;
getline(cin, line);
cout<<endl;
cout << "The pig Latin form of " << line <<" is:\n";

while (line.length() !=0)
{

cout << "Enter a string or, blank to exit." <<endl;
cout << "The program will output the words in Pig Latin."<<endl;
getline(cin, line);
}


/* Process the input line word by word */


while ( line.length() != 0)
{
//cout << "==> Enter line of text or enter return to stop input\n";




int lineLen = line.length();
int wordLen = line.find(' ');

if (wordLen > 0)
{
word = line.substr(0,w ordLen);
line = line.substr(wor dLen+1);

cout << pigLatinString( word) << " ";
}
else
{
cout << pigLatinString( line) <<"\n ";

line = "";
}
}


return 0;
};



////////////////////////////////////////////////////////these are words starting with a vowel
bool isVowel(char ch)
{
switch (ch)
{
case 'A': case 'E': case 'I': case 'O':case 'U':
case 'a': case 'e':case 'i': case 'o': case 'u':
return true;
default: return false;
};
}///////////////////////////////////////////////////////////////end isVowel

string rotate(string pStr)

{
string::size_ty pe len=pStr.length ();

string rStr;

rStr=pStr.subst r(1,len-1)+pStr[0];

return rStr;
}

string pigLatinString( string pStr)

{
string::size_ty pe len;

bool foundVowel;

string::size_ty pe counter;

if (isVowel(pStr[0]))

pStr=pStr+"way" ;

else
{//These are words that didn't start with a vowel



len=pStr.length ();
foundVowel=fals e;



if (isVowel(pStr[0]))

{
foundVowel=true ;
}

else

pStr=rotate(pSt r);

if (!foundVowel)

pStr=pStr.subst r(0,len)+"way";

else

pStr = pStr + "ay";
}
return pStr;

}

[sicarie]

Yeah, I'd use the while loop to test the input, and repeat output, then go on to the program, not do the program in a while loop...`

[ahoway]

Thanks for all the help. I changed my program around and this is what I came up with. It does exactly what the standards called for.

// piglatin_2.cpp : Defines the entry point for the console application.
//
// PigLatin.cpp : Defines the entry point for the console application.
//This program will take in a string of characters from a sentence. It will
//then look at each word and convert the word to Pig Latin. It will then
//put the sentence back toghther in Pig LAtin form. It has a loop inside it
// to continuously test for new strings in which the user types in. If there
//is nothing to be typed in and the NULL condition is satisfied the program will then
//break out of the loop..Does not look for punctuation

#include "stdafx.h"
#include <string>
#include <iostream>
using namespace std;


///////////////////////////////////////////////////////////////////////
///////////////////////FUNCTION LIST///////////////////////////////////////////////
bool isVowels(char x);
void Vowel(string changed);
void nonVowel(char begin, string end);
void changeLine (string line);
void printHeader();

////////////////////////////////////////////////////////////////////////////////////
////////////////////////////////////////////////////////////////////////////////////
////////////////////BEGIN THE MAIN PROGRAM///////////////////////////////////////////


int main()
{

char ch;
string word, first, line;

printHeader();//prints my information
cout <<endl;
cout << "Enter a string or, blank to exit.\n";
cout << "This program will output the words in Pig Latin.\n";
cout <<endl;
getline(cin,lin e);//input a line of words
cout <<endl;
while (line.length()! = 0)//this loop was formed to keep the user able to
//input more sentences to be reconfigured into Pig Latin. If the loop recognizes
//the null space it will break out of the loop and end the program.
{
changeLine(line );// output of the new sentence in Pig Latin
cout<<endl;
cout<<endl;
cout << "Enter a string or, blank to exit.\n";
cout << "This program will output the words in Pig Latin.\n\n";
cout <<endl;
getline(cin,lin e);//input a line of words
}
return 0;
}
/////////////////////////////////////////////////////////////////////////////////
////////////////////////////END OF MAIN//////////////////////////////////////////


bool isVowels(char x) // this is where all of the vowels in the words are found. It will
//read in the word, change the letter to loower case.
{
char low_case = tolower (x);
if (low_case == 'a' )
return true;
else if (low_case == 'e' )
return true;
else if ( low_case== 'i' )
return true;
else if (low_case == 'o' )
return true;
else if (low_case == 'u' )
return true;
else
return false;

}

void changeLine (string line)//this is where the strings are changed. As long as there is
//not a Null character, changeling will look at each word. It will look for the blank spaces
//between the words. One a word is found it is the look at to whether it has a vowel in it or not
// then it is rearranged into a string.
{
string word, first;
char ch;
while (line.length() !=0)//line consist of characters
{
int wordLen = line.find(' ');
if (wordLen >0)
{
word = line.substr(0,w ordLen);
first=word.subs tr(0,1);
ch = first[0];
string notFirst(word,1 );
if (isVowels (ch))// vowel found
{
Vowel(word);
}
else
{
nonVowel(ch,not First);//no vowel found
}
line = line.substr(wor dLen+1);
}
else
{
word = line;
ch = line[0];
string notFirst(word,1 );
if (isVowels (ch))
Vowel(word);
else
nonVowel(ch, notFirst);
line="";
}
}
}
void Vowel(string changed)//what this does is when the string of the new word is brought in
//it is changed due to Pig latin configuration for words that begin with a vowel and then added "way" to the end of the word.
//this new word is then processed out to the string to put back to sentence form.
{
string newWord;
newWord=changed +"way";
cout<<newWord<< " ";
}

void nonVowel(char begin, string end)//what this does is when the string of the new word is brought in
//it is changed due to Pig latin configuration for words that do not begin
//with a vowel and then added "ay" to the end of the word.this new word is then processed
//out to the string to put back to sentence form.
{
string newWord;
newWord=end+beg in+"ay";
cout<<newWord<< " ";
}
void printHeader()//This is the format for my header to print name and class info.
{
cout <<"\Anthony Howay"<<endl;
cout <<"csc 275 Prog 4-Pig Latin" <<endl;
cout <<"09 Nov. 2006"<<endl;

};