on cout,

[vsgdp]

Why cout << "Test: " << foobar() << endl;

calls foobar first? It seems:

cout.operator<< ("Test: ").operator<<(f oobar()).operat or(endl);

would mean "Test: " is output first.

[benben]

Re: on cout,

vsgdp wrote:

Why cout << "Test: " << foobar() << endl;
>
calls foobar first? It seems:
>
cout.operator<< ("Test: ").operator<<(f oobar()).operat or(endl);
>
would mean "Test: " is output first.
>

If you want order then put them in separate statements:

cout << "Test: ";
cout << foobar();
cout << endl;

A chained operation like the one you posted only guarantees that the
outputs are in order. The order of evaluation of subexpressions is up to
the compiler.

Ben