Printing CLA using pointer

[evantri]

Write a C program that will use a char ** pointer to print out each command line argument.

I know that I should use for loop, but I have no idea how to initiate and terminate the loop.

Could someone help me please? Thanx

[dtimes6]

Write a C program that will use a char ** pointer to print out each command line argument.

I know that I should use for loop, but I have no idea how to initiate and terminate the loop.

Could someone help me please? Thanx

main( int argc, char** argv)

* argc is the count of the args.
* argv is the input from the command line

If ur application is Test.exe
u exec it like this: Test.exe -a -b Test.file
argc == 4
argv[0] == "Test.exe"
argv[1] == "-a"
argv[2] == "-b"
argv[3] == "Test.file"

[Banfa]

in main

int main(int argc, char **argp)
{
}

argc holds the number of pointers in the array argp that contain data. Use an integer variable starting at 0 and with a stop condition of <argc in your for loop.

Then access argp[LoopVariable] to get the argument values.

[evantri]

in main

int main(int argc, char **argp)
{
}

argc holds the number of pointers in the array argp that contain data. Use an integer variable starting at 0 and with a stop condition of <argc in your for loop.

Then access argp[LoopVariable] to get the argument values.

I know about the meaning of argv (the command line input) and argc (argument count). so far i can write the code until

int main ( int argc, char ** argv )

{

int i;

char ** print_argv;

for ( print_argv = ...; print_argv != NULL; print_argv ++ )
            {
            // print the argv here
            }

}

Am I goin in the right track? Do I have to two FOR loops instead of one FOR loop? How do I initiate the loop? Thanx

[evantri]

Anyway, what's wrong with my code here?

int main ( int argc, char ** argv )

{

// Mainline Variable Declarations
FILE * output = stdout;

int i; // Loop index

char ** print_argv; // Pointer of pointer to character ( array of strings )

fprintf ( output, "\n" );

for ( print_argv = argv[0], i = 0; print_argv != NULL; print_argv ++, i ++ )
        {
        fprintf ( output, "argv[%d] is %s\n", i, print_argv );
        }

fprintf ( output, "\n" );

}

[Banfa]

Declare

char ** print_argv;

as

char * print_argv;

[evantri]

Declare

char ** print_argv;

as

char * print_argv;

But the specification requires that the pointer that I suppose to use is a type of ** pointer? So how do I modify the FOR loop using a char ** pointer?