Simple Iterator question

[RishiD]

Hi,

I am using an iterator on a list, I wanted to know is there a simple
way to erase() the current element the iterator is pointing to and move
the iterator forward one?

The only way I can think of doing this is making a temp iterator equal
to orig position, then erasing, and setting the original iterator to
temp iterator++

Basically asking if there is a way to do the code below in two steps
instead of three.

Thanks,

RishiD

// move private iterator forward and eliminate person
void movingForward()
{
list<Person>::i terator tempIter = privIter;
circle.erase(pr ivIter);
privIter = tempIter++;
}

[Victor Bazarov]

Re: Simple Iterator question

RishiD wrote:

I am using an iterator on a list, I wanted to know is there a simple
way to erase() the current element the iterator is pointing to and
move the iterator forward one?
[..]

Is this a trick question? 'std::list::era se' has a return value
type, use it.

V
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[RishiD]

Re: Simple Iterator question


Victor Bazarov wrote:

RishiD wrote:

I am using an iterator on a list, I wanted to know is there a simple
way to erase() the current element the iterator is pointing to and
move the iterator forward one?
[..]

>
Is this a trick question? 'std::list::era se' has a return value
type, use it.
>
V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

Haha sorry. My professor told me otherwise, thanks.

Sorry for wasting your time.

[Daniel T.]

Re: Simple Iterator question

In article <1162170693.977 775.159550@b28g 2000cwb.googleg roups.com>,
"RishiD" <rishid@gmail.c omwrote:

Hi,
>
I am using an iterator on a list, I wanted to know is there a simple
way to erase() the current element the iterator is pointing to and move
the iterator forward one?

Yes, simply call erase() and assign the return value to the iterator
object passed in.

The only way I can think of doing this is making a temp iterator equal
to orig position, then erasing, and setting the original iterator to
temp iterator++
>
Basically asking if there is a way to do the code below in two steps
instead of three.
>
Thanks,
>
RishiD
>
// move private iterator forward and eliminate person
void movingForward()
{
list<Person>::i terator tempIter = privIter;
circle.erase(pr ivIter);
privIter = tempIter++;
}

void movingForward()
{
privIter = circle.erase( privIter );
}

or since you are working with a list, you could:

void movingForward()
{
circle.erase( privIter++ );
}

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[rep_movsd]

Re: Simple Iterator question

Hi

Why not

circle.erase(pr ivIter++);

privIter++ increments the iterator and returns the previous value
voila....

It would work even if the container didnt return an iterator from
erase()


Regards
Vivek

[Kai-Uwe Bux]

Re: Simple Iterator question

rep_movsd wrote:

Hi
>
Why not
>
circle.erase(pr ivIter++);
>
privIter++ increments the iterator and returns the previous value
voila....
>
It would work even if the container didnt return an iterator from
erase()

By container, you mean std::list: the idiom you propose does not work for
std::vector because of iterator invalidation. Using the return from erase()
provides the more robust code -- you could change the container to another
sequence type.


Best

Kai-Uwe Bux

[Daniel T.]

Re: Simple Iterator question

"rep_movsd" <rep.movsd@gmai l.comwrote:

Why not
>
circle.erase(pr ivIter++);

It's not as general purpose because it doesn't work for vector and may
not work for deque depending on where in the container the iterator is.

When you have a choice between a method that works for all Sequences and
one that only works for some Sequences, always choose the more general
approach unless you information that the specific method is faster.

privIter++ increments the iterator and returns the previous value
voila....
>
It would work even if the container didnt return an iterator from
erase()

All Sequences must return an iterator from erase, they don't all have to
keep the iterator valid.

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