int n , i = 10, j =20, y=100, x = 3;
n = ( i < j ) || (y +=i) ;
cout<<y;
// why y = 100, but not 110, as y +=i , y = y + i
n = ( i < j ) || (y +=i) ;
cout<<y;
// why y = 100, but not 110, as y +=i , y = y + i
-
-
Re: Strange problem...
howa wrote:The above evaluates left-to-right.int n , i = 10, j =20, y=100, x = 3;
>
n = ( i < j ) || (y +=i) ;
Since it is a logical 'or', if the first expression,
(i < j), evaluates to 'true', then the second expression,
(y += i), is NOT evaluated.
>
cout<<y;
>
// why y = 100, but not 110, as y +=i , y = y + i
> -
Re: Strange problem...
In article <1161916770.479 434.313150@e3g2 000cwe.googlegr oups.com>,
howa <howachen@gmail .comwrote:This is so-called short-circuting of expressions.> int n , i = 10, j =20, y=100, x = 3;
>
> n = ( i < j ) || (y +=i) ;
>
> cout<<y;
>
>// why y = 100, but not 110, as y +=i , y = y + i
When expressions are seperated by || it will take each in turn,
if the value of the current is false, it continues to the next;
if the value of the current is true, the full expression is deemed
successful and no need to continue to be more successful
therefore subsequent parts are not evaluated to be more successful.
In your specific example i is < j, therefore, the y+=i expression
is not evaluated.
--
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