hours

[muna123]

Hi, i need help in c prog not c ++ so please don't tell me c ++ code :D

m_hrs is 8.

hrs is double

hrs= (m_hrs * 20) / 60;

printf(" hrs is %.2lf", hrs);

ans: 2.00 not 2.67

the problem is i am not getting 2.67 but when i calculated with calculator i am getting 2.667.

Thanks for help

[arne]

Hi, i need help in c prog not c ++ so please don't tell me c ++ code :D

m_hrs is 8.

hrs is double

hrs= (m_hrs * 20) / 60;

printf(" hrs is %.2lf", hrs);

ans: 2.00 not 2.67

the problem is i am not getting 2.67 but when i calculated with calculator i am getting 2.667.

Thanks for help

You do the calculation (m_hrs * 20) / 60 with integers (I guess m_hours has type int?) and cast the result to double. You can either define m_hrs to be of type double or change your code to

hrs = ((double)m_hrs*20/60);

[muna123]

You do the calculation (m_hrs * 20) / 60 with integers (I guess m_hours has type int?) and cast the result to double. You can either define m_hrs to be of type double or change your code to

hrs = ((double)m_hrs*20/60);

Thanks it worked !!!

[arne]

Thanks it worked !!!

I hope you have understood why? :)