c program to implement newton raphson method for finding roots of a polynomial

[sekitoleko]

c program for newton raphson algorithm for finding roots of a polynomial

[r035198x]

c program for newton raphson algorithm for finding roots of a polynomial

Why won't you try to write it yourself and then post at a more specific problem?

[sekitoleko]

c program for newton raphson using a for loop

how can i implement a c progran for newton raphson algorithm using a for loop?

[Banfa]

how can i implement a c progran for newton raphson algorithm using a for loop?

Please dont double post.

Please do have an attempt yourself first.



Do you know how the newton raphson method works?

[sekitoleko]

c program for newton raphson method

#include<stdio. h>
/Calculate j(10) from j(0)
int main()
{
int n;
double j=0.6;
printf("forward iterations\n");
printf("initial estimate:j(0)=% g\n",j);
for(n=1,n<=10,n ++)
j=1-(j*n);
printf("j(%d)=% g\n",n,j);
}
return 0;
}
this code is not helping me find roots of( x*x-2).What do I need to change?

[iknc4miles]

Ok, let me see if I understand your code.

I'm a numerical methods and modeling engineer so I should understand the Newton-Raphson Method to be:

j( i+1 ) = j( i ) - [ j( i )^2 - 2 ] / [ 2*j( i ) ] for the function f( j ) = (j*j - 2).

So, you should step i forward until f( j ) is within your tolerance of 0. Then your answer should be your last j.

Here's some pseudocode:

i = 0

while( absoluteValue( f( j ) ) > toleranceValue)
{
j = j - [ f( j ) ] / [ df( j ) ];
i++;
}
printOut("Root of Function is at %g After %d Iterations" j, i );

When you write this out in whatever language you want, should work.

- Miles

[Banfa]

Please DON'T double post (hmmm I seem to be repeating myself here)

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