Pointer troubles

[ShowDown]

im recently working on a project, where I need to read one line, check it for data, then delete some of the data in the string, im using substr. The problem comes when I have to do it in functions.
sorry if i confuse you, i'll try give a example.
FX.

int DoSome(string *inp) {
if (inp.substr(0,6)=="myflow") {   // here's my problem, inp only points, and don't got the method substr.
inp = inp.substr(6);
// lot of code here
}
}

int main() {
   string hello;
   hello = "myflow123";
   DoSome(&hello);
}

Sorry its not snips, becusase its too big and this would really simplify it, plus make it faster.

Regards

[Jai Vrat Singh]

I am not sure if you are saying the it soes not gets substr method of std::string class , but effect you are trying to achive can be done by

int DoSome(string *inp) {
if ((*inp).substr(0,6)=="myflow") {   // here's my problem, inp only points, and don't got the method substr.
(*inp) = (*inp).substr(6);
// lot of code here
}
return (0);
}

int DoSome(string &inp) {
if (inp.substr(0,6)=="myflow") {   // here's my problem, inp only points, and don't got the method substr.
 inp = inp.substr(6);
// lot of code here
}
return (0);
}


int main() {
   string hello;
   hello = "myflow123";
   std::cout<<" Before hello is >>"<<hello<<"<<\n";
   DoSome(&hello);
   std::cout<<" After hello is >>"<<hello<<"<<\n";

   string junk;
   junk = "myflow123";
   std::cout<<" Before junk is >>"<<junk<<"<<\n";
   DoSome(junk);
   std::cout<<" After junk is >>"<<junk<<"<<\n";


}

Code you gave takes a poiter as input and you are using . operator , which will give you compile time errors. You can modify it as above or the best would be use references like

int DoSome(string &inp) {
if (inp.substr(0,6)=="myflow") {   // here's my problem, inp only points, and don't got the method substr.
 inp = inp.substr(6);
// lot of code here
}
return (0);
}

[ShowDown]

Thanks.
Thats exactly what I needed :D
Now my project finaly can continue

regards