new replacing malloc

[RS24]

Hi!
Can someone tell me the correct answer for these ...

Replace the following code using new operator-
(Assume int is 2 bytes)
#define MAXROW 3
#define MAXCOL 4

1.)
void main()
{
int (*p)[MAXCOL];
p=(int(*) [MAXCOL]) malloc(MAXROW*s izeof(*p));
}


2.)
void main()
{
int (*p)[MAXROW][MAXCOL];
p=(int(*) [MAXROW][MAXCOL]) malloc(sizeof(* p));
}


3.)
void main()
{
int **p,i;
p=new int *[MAXROW];
for(i=0;i<MAXRO W;i++)
p[i]=new int[MAXCOL];
}

4.)
void main()
{
int **p,i;
p=(int**)malloc (MAXROW*sizeof( int *));
p[0]=(int *)malloc(MAXROW *MAXCOL*sizeof( int));
for(i=0;i<MAXRO W;i++)
p[i]=p[0]+i*MAXCOL;
}

[D_C]

It is unlikely until you tell us what the question is. Is it "how to rewrite the following code using new rather than malloc"?

[RS24]

It is unlikely until you tell us what the question is. Is it "how to rewrite the following code using new rather than malloc"?

Yes! That's exactly what the question is !

[Banfa]

I think you should probably attempt this yourself first (it looks like course/home work to me).

Bear in mind that these are equivilent

int *pi = malloc(5 * sizeof(int));

int *pi = malloc(5 * sizeof *pi);

int *pi = new int[5];

[RS24]

I think you should probably attempt this yourself first (it looks like course/home work to me).

Bear in mind that these are equivilent

int *pi = malloc(5 * sizeof(int));

int *pi = malloc(5 * sizeof *pi);

int *pi = new int[5];

==============

Hi Ben,

No, its not a course/home work !
I n fact the question is from a book and they have given the answers too . but I am not sure that the answers are right. i have an interview 2morrow n it will be really helpful if u check these-

(these r the answers from the book itself)

1. p=new int [MAXROW][sizeof(*p)/sizeof(int)];

2. p=new int[1]MAXROW][MAXCOL];

3. this one i think is correct
p=new int*[MAXROW];
for(----)
p[i]=new int [MAXCOL];


4. this too i think is correct
p=new int*[MAXROW];
p[0]=new int [MAXROW * MAXCOL];

[Banfa]

This is probably late (sorry I shall blame the cold that has wiped out the past couple of days) but I think that all there solutions are syntatically correct. Not that I think they are necessarily a good idea.