reverse

[shahrukh]

i have to input a number and print the reverse of the number. and also the sum of all the numbers which is given as input i.e. the input is 123. the sum is 6 and multiplication of the numbers i.e. 123. the multiplication is 6.

similarly i have to input a text and print the reverse of it i.e. abc. the output should be cba. plz if anyone have their solution then reply with their logics

[ltgbau]

	// in this code i treat the input number as a string
	// and i assume that the input is valid (it means the input is a number
	// and it doesn't contant any non-numeric character...
	cout<<"input a number:";
	char strNum[10]="";
	cin>>strNum;
	cout<<endl;
	// calculate sum and mul of all figures to form the input number
	int sum=0;
	int mul=1;
	int len=(int)strlen(strNum);
	if(len<=0)
		return;
	char strTemp[2]="";
	int val;
	for(int i=0; i<len; i++)
	{
		strTemp[0]=strNum[i];
		val=atoi(strTemp);
		sum+=val;
		mul*=val;
	}
	cout<<"Sum="<<sum<<endl<<"Mul="<<mul<<endl;	// done
	// print reversed number
	strrev(strNum);
	cout<<"Reversed number="<<strNum;

[koder]

Hi,posting the necessery kode,for what u askd,try out the string reversal by your self,if u find difficulties,pl ease do not hesitate to ask

#include<stdio.h>
#include<string.h>



int get_sum(int);
int get_prod(int);
int get_rev(int);

main()
 {
   int pnum=0,rev_num,i,prod,sum;
   int  ch=0;
   printf("\n enter the number");
   scanf("%d",&pnum);

    while(1)
     {
        printf("\n enter the operation ");
        printf("\n 1:reverse \t 2:sum \t 3:multiplication");
        scanf("%d",&ch);
        printf("\n u choosed the  option :%d",ch);

int get_rev(int pnum)
  {
   int kum=0,rev=0,pum=pnum;
   while(pnum!=0)
    {
   kum=pnum%10;
   rev=rev*10+kum;
   pnum=pnum/10;
   }
  return rev;
 }

int get_prod(int pnum)
  {
   int kum=0,prod=1,pum=pnum;
   while(pnum!=0)
    {
   kum=pnum%10;
   prod=prod*kum;
   pnum=pnum/10;
   }

   return prod;
 }
int get_sum(int pnum)
  {
   int kum=0,sum=0,pum=pnum;
   while(pnum!=0)
    {
   kum=pnum%10;
   sum=sum+kum;
   pnum=pnum/10;
   }
  return sum;
 }

   sum=sum+kum;
   pnum=pnum/10;
   }
  return sum;
 }

compiled and tested with gcc.