integers as a string

[Mike Vallely]

If anyone could help me with my problem I'd greatly appreciate it, this
question probably has a quick easy answer but I've been wanting to punch the
wall for the last hour because of it.

I have a string IDNUM = "12345";

I need to do simple arithmetic with the integers in this string.

The way I've been trying and failing is by doing something similar to this:



int x , y;
string i1=IDNUM.substr (0,1); //sets i1 = 1 hopefully
x = atoi(i1); //Here, I fail to convert the integer in the string to
the type integer
y = x + 5;


I know the "x = atoi(i1)" is the root of all of my problems. But I do not
know how to fix it, and I have two books both of which do not touch on
atoi( ) at all. (buying a new book right now isn't the most convenient
option). At the time this section of code executes, the integers in the
string could be anything, so I can't just plug in the numbers.

So to sum up my question, I have a string of integers named IDNUM, and I
cannot figure out how to use the integers in this string outside of
outputting the string and then having the user re-enter the numbers they see
into an INT variable, which is stupid. Thanks in advance for any help.

-Mike V

[Mike Vallely]

Re: integers as a string


Nevermind, I just googled it and got the exact answer I needed. Probably
should have done that beforehand.

-Mike V

[Ali R.]

Re: integers as a string


"Mike Vallely" <mkNOSPAMvallel y@hotmail.com> wrote in message
news:HUSrb.2797 8$kS.13853@news svr31.news.prod igy.com...[color=blue]
> If anyone could help me with my problem I'd greatly appreciate it, this
> question probably has a quick easy answer but I've been wanting to punch[/color]
the[color=blue]
> wall for the last hour because of it.
>
> I have a string IDNUM = "12345";
>
> I need to do simple arithmetic with the integers in this string.
>
> The way I've been trying and failing is by doing something similar to[/color]
this:[color=blue]
>
>
>
> int x , y;
> string i1=IDNUM.substr (0,1); //sets i1 = 1 hopefully
> x = atoi(i1); //Here, I fail to convert the integer in the string to
> the type integer
> y = x + 5;
>
>
> I know the "x = atoi(i1)" is the root of all of my problems. But I do not
> know how to fix it, and I have two books both of which do not touch on
> atoi( ) at all. (buying a new book right now isn't the most convenient
> option). At the time this section of code executes, the integers in the
> string could be anything, so I can't just plug in the numbers.
>
> So to sum up my question, I have a string of integers named IDNUM, and I
> cannot figure out how to use the integers in this string outside of
> outputting the string and then having the user re-enter the numbers they[/color]
see[color=blue]
> into an INT variable, which is stupid. Thanks in advance for any help.
>
> -Mike V
>
>
>[/color]

The root of the problem is that you don't know how to use string.

string str = "12345";
int x = atoi(str.c_str( ));

[Tim Threlfall]

Re: integers as a string

Hi

atoi() takes a const char* as an argument, not an std::string. So you
would need to do atoi(i1.c_str() );

You could also use stringstreams instead of atoi() to convert an
std::string into an int, something like this


template<typena me RT, typename T, typename Trait, typename Alloc>
RT ss_atoi( std::basic_stri ng<T, Trait, Alloc>& the_string )
{
std::basic_istr ingstream< T, Trait, Alloc> temp_ss(the_str ing);
RT num;
temp_ss >> num;
return num;
}

Which you would call as int x = ss_atoi<int>(i1 );


Or you could use boost::lexical_ cast.