help me to understand the declaration as well as the reason

[srikar]

Hi I am having a problem using typedef

what does these declaration mean?

typedef gtb(string_t, tt_type_enum) tt_type_table( &stringless, &stringequal s );
typedef gtb(string_t,tt _qual_enum) tt_qual_table( &stringless, &stringequal s);

where gtb is a macro
#define gtb(key_type,va lue_type) name3(value_typ e,tb,key_type)
#define name3(a,b,c) _name3_aux(a,b, c)
#define _name3_aux(a,b, c) a##b##c
'#" is for concatenation

string_t is pointer to class string_rec
tt_type_enum is of type enum

stringless is (int stringless(tb__ item_t a, tb__item_t b))
stringeuals is (int stringequals(tb __item_t a, tb__item_t b))

when i am using the first declarations in my code I am getting error
syntax error before `(' token, for both typedefs.

help me to understand the declaration as well as the reason

for the syntax error..

regards

srikar

[srikar]

any one suggest me

[Banfa]

It is very confusing

typedef gtb(string_t, tt_type_enum) tt_type_table( &stringless, &stringequal s );

when we apply the gtb macro ends up as

typedef tt_type_enumtbs tring_t tt_type_table( &stringless, &stringequal s );

I think the & are wrong but may be the compiler does care.

Looks like it is may be trying to declare a type that is a pointer to a function that returns tt_type_enumtbs tring_t and takes 2 other pointers to functions as parameters.