NRV question

[jronald]

A sample in <inside c++ object model>:

X bar()
{
X xx;
//...
return xx;
}

void bar(X &__result)
{
__result.X::X() ;
//...
return;
}

Why X::X() is called inside bar? I think it should be called before bar, for
better semantic.To always reset a input parameter (by calling its
constructor here) is senseless.

Is the latter better than the former anyway?
X x0=bar();
1. X::X() is called inside bar
X x0;
bar(x0);
2. outside
X x0;
x0.X::X();
bar(x0);

[Pete Becker]

Re: NRV question

jronald wrote:

>
Why X::X() is called inside bar? I think it should be called before bar, for
better semantic.To always reset a input parameter (by calling its
constructor here) is senseless.
>

The compiler doesn't know at the point where it calls bar() how bar is
going to create the returned object. Suppose it does this:

X bar()
{
X xx(3);
return xx;
}

Now default constructing the return object at the point of the call is
simply wrong.

--

-- Pete

Author of "The Standard C++ Library Extensions: a Tutorial and
Reference." For more information about this book, see
www.petebecker.com/tr1book.

[jronald]

Re: NRV question

I was a little confused just now. You are right.
It's the function generated the object.
The complier treats "X x0;" a memory allocation only, which is different
from C++ semantic. In C++ semantic, "X x0" imply a call to the default
constructor.

"Pete Becker" <petebecker@acm .org>
??????:wYudnbP-7MXgkpHYnZ2dnUV Z_tOdnZ2d@gigan ews.com...

jronald wrote:

>>
>Why X::X() is called inside bar? I think it should be called before bar,
>for better semantic.To always reset a input parameter (by calling its
>constructor here) is senseless.
>>

>
The compiler doesn't know at the point where it calls bar() how bar is
going to create the returned object. Suppose it does this:
>
X bar()
{
X xx(3);
return xx;
}
>
Now default constructing the return object at the point of the call is
simply wrong.
>
--
>
-- Pete
>
Author of "The Standard C++ Library Extensions: a Tutorial and Reference."
For more information about this book, see www.petebecker.com/tr1book.

[Pete Becker]

Re: NRV question

jronald wrote:

It's the function generated the object.
The complier treats "X x0;" a memory allocation only, which is different
from C++ semantic. In C++ semantic, "X x0" imply a call to the default
constructor.

Right. You have to be extra careful in discussions about what's going on
behind the scenes, because the compiler can do things that are different
from what the code suggests, provided the behavior of the program is the
same.

--

-- Pete

Author of "The Standard C++ Library Extensions: a Tutorial and
Reference." For more information about this book, see
www.petebecker.com/tr1book.