Operator overloading problem

[Matti]

Hello,

I have a problem comparing 2 values of type AnsiString using the ==
operator (C++ Builder 5).

I use another class called TValue, which also defines the == operator.
Now when I
try to compare 2 AnsiString Values the == operator of class TValue is
invoked.

How can I avoid that and force my program to use the operator defined
for the
AnsiString class.

Here you can see a short example of what I mean.

TValue::TValue( AnsiString Val) {
}

bool TValue::operato r==(const TValue &iVal2) const {
return true;
}

test () {
AnsiString Val1, Val2;
Val1 = "Test";
Val2 = "Test";

if (Val1 == Val2) {
}
}

Thank you for your help,

Matti

[Gianni Mariani]

Re: Operator overloading problem

Matti wrote:[color=blue]
> Hello,
>
> I have a problem comparing 2 values of type AnsiString using the ==
> operator (C++ Builder 5).
>
> I use another class called TValue, which also defines the == operator.
> Now when I
> try to compare 2 AnsiString Values the == operator of class TValue is
> invoked.
>
> How can I avoid that and force my program to use the operator defined
> for the
> AnsiString class.
>
> Here you can see a short example of what I mean.
>
> TValue::TValue( AnsiString Val) {
> }
>
> bool TValue::operato r==(const TValue &iVal2) const {
> return true;
> }
>
> test () {
> AnsiString Val1, Val2;
> Val1 = "Test";
> Val2 = "Test";
>
> if (Val1 == Val2) {
> }
> }
>
> Thank you for your help,[/color]

A complete compilable example would really help.

It seems to me that if what your saying is true, your compiler is not
conforming to the standard. In the example, Val1 == Val2, you should
have the AnsiString operator == called. If what I read from the
standard is true, conversion + calling operator == should never be
preferred over just calling operator ==.

[David B. Held]

Re: Operator overloading problem

"Matti" <xmrf@yahoo.d e> wrote in message
news:a4b6eb66.0 310111046.2be4e 9d0@posting.goo gle.com...[color=blue]
>
> I have a problem comparing 2 values of type AnsiString
> using the == operator (C++ Builder 5).
> [...][/color]

The best place to ask this is
borland.public. cppbuilder.lang uage.cpp. But before you
ask your question there, reduce your problem to a self-
contained program of 50 lines or less, if you can. Odds
are, by the time you do that, you'll see that you have an
error someplace else.

Dave



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[Sergey Tolstov]

Re: Operator overloading problem


"Matti" <xmrf@yahoo.d e> wrote in message
news:a4b6eb66.0 310111046.2be4e 9d0@posting.goo gle.com...[color=blue]
> Hello,
>
> I have a problem comparing 2 values of type AnsiString using the ==
> operator (C++ Builder 5).
>
> I use another class called TValue, which also defines the == operator.
> Now when I
> try to compare 2 AnsiString Values the == operator of class TValue is
> invoked.
>
> How can I avoid that and force my program to use the operator defined
> for the
> AnsiString class.
>
> Here you can see a short example of what I mean.
>
> TValue::TValue( AnsiString Val) {
> }[/color]

Use "explicit" keyword in your conversion constructor.

explicit TValue::TValue( AnsiString Val) {
}