Hello!
Which operatiaon causes -1.#IND ? I use complex numbers. Thank you!
Erich
Which operatiaon causes -1.#IND ? I use complex numbers. Thank you!
Erich
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Re: -1.#IND
Hi,
I believe it is an infiinite number (you might have done a divide by zero
and interrupts turned off). I think you can find it in the manuals at intel
for the processor you are using (the floating parts).
Regards, Ron AF Greve.
"Erich Reisenhofer" <erich.reisenho fer@gmx.at> wrote in message
news:3f851a37$0 $15182$3b214f66 @aconews.univie .ac.at...[color=blue]
> Hello!
>
> Which operatiaon causes -1.#IND ? I use complex numbers. Thank you!
>
> Erich
>
>[/color]
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Re: -1.#IND
In article <3f851a37$0$151 82$3b214f66@aco news.univie.ac. at>,
erich.reisenhof er@gmx.at says...[color=blue]
> Hello!
>
> Which operatiaon causes -1.#IND ? I use complex numbers. Thank you![/color]
That's how Microsoft's compilers print out a Quiet NaN (Not a Number).
It's typically the result of working with a variable that hasn't been
initialized (the IND stands for "indefinite " if I'm not mistaken).
Another post mentioned infinity. At least with MS's compilers, a
infinity will print out as -1.#INF. This is typically produced by a
division that produces a result too large to represent, such as
something like 1e+300/1e-300. With infinite range available, this would
produce 1e+600, but a double normally tops out at around 1e+308.
--
Later,
Jerry.
The universe is a figment of its own imagination.
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