casting

[omariqbalnaru@inbox.com]

#include<iostre am>
using namespace std;

int main()
{

int i, *pi;
float f, *pf;

i = 1024;
pi = &i;

pf = (float *) pi;

f = *pf;

cout << " i = " << i << " f = " << f << "\n \n";


f = i;

cout << " i = " << i << " f = " << f << "\n \n";

return 0;

}

In the statement:

pf = (float *) pi;

of the above program. Is that what we call casting of a int pointer to
a float pointer?

[Frederick Gotham]

Re: casting

omariqbalnaru@i nbox.com posted:

#include<iostre am>
using namespace std;
>
int main()
{
>
int i, *pi;
float f, *pf;
>
i = 1024;
pi = &i;
>
pf = (float *) pi;

Here you cast an "int*" to "float*".

The resultant address may very well be corrupted. The following isn't
guaranteed to work:

int i;

int *pi = &i;

float *pf = (float*)&i;

int *pi2 = (int*)pf;

assert(pi2 == pi);

--

Frederick Gotham