Can cout do like printf("Name: %s, Age: %d\n",name,age)?

[cylin]

Dear all,

To do below is too long.
cout << "Name: " << name << ", Age: " << age << endl;
Can cout use "%" to implement?
Thanks.

cylin.

[Sam Holden]

Re: Can cout do like printf(&quot;Na me: %s, Age: %d\n&quot;,name ,age)?

On Tue, 19 Aug 2003 18:54:29 +0800, cylin <cylin@avant.co m.tw> wrote:[color=blue]
> Dear all,
>
> To do below is too long.
> cout << "Name: " << name << ", Age: " << age << endl;[/color]

If 20 characters of typing is enough to make you want to avoid
type safety, then I don't C++ is the language for you. :)
[color=blue]
> Can cout use "%" to implement?[/color]

No.

--
Sam Holden

[Peter van Merkerk]

Re: Can cout do like printf(&quot;Na me: %s, Age: %d\n&quot;,name ,age)?

> To do below is too long.[color=blue]
> cout << "Name: " << name << ", Age: " << age << endl;[/color]

Why it is too long?
If you would remove the spaces around the '<<' operators (just like the
printf), the cout version is only 4 character longer. That seems to be a
small price to pay for the type safety you get with cout.
[color=blue]
> Can cout use "%" to implement?[/color]

No.

--
Peter van Merkerk
peter.van.merke rk(at)dse.nl

[John Harrison]

Re: Can cout do like printf(&quot;Na me: %s, Age: %d\n&quot;,name ,age)?


"cylin" <cylin@avant.co m.tw> wrote in message
news:bhsvii$2rh fn$1@ID-154203.news.uni-berlin.de...[color=blue]
> Dear all,
>
> To do below is too long.
> cout << "Name: " << name << ", Age: " << age << endl;
> Can cout use "%" to implement?
> Thanks.
>
> cylin.
>[/color]

No, but boost do a format library that adds this to C++

http://www.boost.org/libs/format/index.htm

john

[Bob Jacobs]

Re: Can cout do like printf(&quot;Na me: %s, Age: %d\n&quot;,name ,age)?

"cylin" <cylin@avant.co m.tw> wrote in message
news:bhsvii$2rh fn$1@ID-154203.news.uni-berlin.de...[color=blue]
> Dear all,
>
> To do below is too long.
> cout << "Name: " << name << ", Age: " << age << endl;
> Can cout use "%" to implement?
> Thanks.[/color]

Your two examples are not equivalent. In the version using cout you flush
the output stream, whereas in the printf version you don't.

[Roy Smith]

Re: Can cout do like printf(&quot;Na me: %s, Age: %d\n&quot;,name ,age)?

In article <bhsvii$2rhfn$1 @ID-154203.news.uni-berlin.de>,
"cylin" <cylin@avant.co m.tw> wrote:
[color=blue]
> Dear all,
>
> To do below is too long.
> cout << "Name: " << name << ", Age: " << age << endl;
> Can cout use "%" to implement?
> Thanks.
>
> cylin.
>
>
>[/color]

Check out boost.format (http://www.boost.org/libs/format/index.htm)

[Mike Wahler]

Re: Can cout do like printf(&quot;Na me: %s, Age: %d\n&quot;,name ,age)?

cylin <cylin@avant.co m.tw> wrote in message
news:bhsvii$2rh fn$1@ID-154203.news.uni-berlin.de...[color=blue]
> Dear all,
>
> To do below is too long.
> cout << "Name: " << name << ", Age: " << age << endl;[/color]

Removing unnecessary whitepace and using
same newline expression in order to form
a valid comparision:

printf("Name: %s, Age: %d\n",name,age) ;

cout<<"Name: "<<name<<", Age: "<<age<<'\n ';

Is an extra four characters really too high
a price to pay for type safety?
[color=blue]
> Can cout use "%" to implement?[/color]

I suppose one could write some code to simulate
it, but what's the point?

Also note that 'printf()' is just as valid
(but less safe) a function in C++ as are the
stream inserters.

If you insist upon using '%' specifiers, why not just
use 'printf()'?

-Mike